When you shine a lite through a prism is reflects out light through all of the edges and causes light separation. Or just simply shine a laser through the edge of a sideways piece of glass.
I hope that this was helpful for you.
Answer:
a) q = 6.27 10⁻¹⁹ C
, b) 4 electron
Explanation:
a) In this configuration of the Mullikan experiment, the sum of the forces is zero, let's use the equilibrium law of / newton
- W = 0
q E = mg
q = mg / E
Let's calculate
q = 1.1 10⁻¹⁴ 9.8 / 1.72 10⁵
q = 6.27 10⁻¹⁹ C
b) Millikan found that the minimum charge that can exist is
q₀ = 1.6 10⁻¹⁹ C
So all charge are an integer multiple of this minimum value.
q = n q₀
n = q / q₀
n = 6.27 10⁻¹⁹ / 1.6 10⁻¹⁹
n = 3.92 = 4
In our drop we have 4 electrons
Answer:
Kinetic energy = (1/2) (mass) (speed²)
First object: (1/2) (2 kg) (2 m/s)² = 4 joules .
Second object: (1/2) (4 kg) (3 m/s)² = 18 joules .
The second object had more kinetic energy than the first one had.
Explanation:
Answer:
e)
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Explanation:
= Magnitude of electric field = 5 V/m
= Area of window = 1.5 m²
= speed of electromagnetic wave = 3 x 10⁸ m/s
= time interval = 1 h = 3600 sec
radiation energy is given as
![U = (0.5)\epsilon _{o}E_{o}^{2}cA\Delta t](https://tex.z-dn.net/?f=U%20%3D%20%280.5%29%5Cepsilon%20_%7Bo%7DE_%7Bo%7D%5E%7B2%7DcA%5CDelta%20t)
![U = (0.5)(8.85\times 10^{-12})(5)^{2}(3\times 10^{8})(1.5)(3600)](https://tex.z-dn.net/?f=U%20%3D%20%280.5%29%288.85%5Ctimes%2010%5E%7B-12%7D%29%285%29%5E%7B2%7D%283%5Ctimes%2010%5E%7B8%7D%29%281.5%29%283600%29)
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