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3 years ago

When is something weightless

1 answer:

5 0

The phenomenon of "weightlessness" occurs when there is no force of support on your body. When your body is effectively in "free fall", accelerating downward at the acceleration of gravity, then you are not being supported.

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A 6.25-kg bowling ball moving at 8.95 m/s collides with a 0.95-kg bowling pin, which is scattered at an angle of θ = 27.5° from

Archy [21]

Answer:

-6.34 degrees.

Explanation:

Because this is a collision we can use the formula of linear momentum conservation.

$m_1*v_{o1}+m_2*v_{o2}=m_1*v_{f1}+m_2*v_{f2}$

The pin has an angle so it has two components of velocity, so:

$v_x=V*cos(\theta)\hat{i}\\v_y=V*sin(\theta)\hat{j}\\\\v_x=11.6*cos(27.5^o)=(10.3m/s)\hat{i}\\v_y=11.6*sin(27.5^o)=(5.4m/s)\hat{j}$

applying the first formula:

$6.25kg*(8.95m/s)\hat{i}+0=6.25kg*v_{f}+0.95kg*(10.3m/s(\hat i)+5.4m/s(\hat j))\\\\v_f=\dfrac{6.25kg*(8.95m/s)\hat{i}-0.95kg*(10.3m/s(\hat i)+5.4m/s(\hat j))}{6.25kg}\\v_f=7.38m/s(\hat i)-0.82m/s(\hat j)$

The angle is given by:

$\theta_b=acrtg(\dfrac{v_f(\hat j)}{v_f(\hat i)})\\\\\theta_b=arctg(\frac{-0.82m/s}{7.38m/s})\\\theta_b=-6.34^o$

the angle is -6.34 degrees.

4 0

3 years ago

When 560,000 is written in scientific notation, what is the power of 10?

tensa zangetsu [6.8K]

5.6•10^5 so it’s to the power of positive 5

3 0

3 years ago

Read 2 more answers

Diffraction of sound waves is demonstrated when sound waves with a frequency of 1300 Hz from a distant source are diffracted thr

Tresset [83]

Answer:

39.05°

Explanation:

As we know that, the diffraction is the phenomena of bending of light when it passes through an obstacle.

Mathematically,

$dsin\theta=n\lambda$

Here, d is slit width, $\lambda$ is the wavelength, n is the order, $\theta$ is the angle.

Given that, d is 84 cm, n is 2, and the wavelength can be calculated as,

$\lambda=\frac{c}{f}$

Here, c is the speed of sound and f is the frequency of sound wave.

Here, c is 343 m/s and f is 1300 Hz,

Therefore,

$\lambda=\frac{343 m/s}{1300 Hz}\\\lambda=0.264m$

Recall diffraction equation in term of $sin\theta$ .

$sin\theta=\frac{n\lambda}{d}$

Put all the variables.

$sin\theta=\frac{2\times 0.264 m}{84 cm}\\sin\theta=\frac{2\times 0.264 m}{0.84 m}\\\theta=39.05^{\circ}$

Therefore, it is the required angle between the first 2 order of diffraction.

3 0

3 years ago

Expand (2x + y) (2x - y).

KiRa [710]

Answer: 4x²-y²

Explanation:

FORMULA

a²-b²=(a+b)(a-b)

-----------------------------

(a+b)(a-b)=a²-b²

(2x+y)(2x-y)=(2x)²-(y)²

=4x²-y²

Hope this helps!! :)

Please let me know if you have any question

8 0

3 years ago

How does the mass of an object change the gravitational pull on two objects in a system? How does the distance between objects i

LuckyWell [14K]

Answer:The greater the mass, there greater then gravitational pull on their objects.

There greater the distance,the lower the gravitational pull between the object

Explanation:

Gravitational pull(force) is directly proportional to the products Of The masses. therefore if the mass increase,the gravitational pull(force) also increases.

Gravitational pull(force) is inversely proportional to distance.if the distance between the objects increases,the gravitational pull(force) decreases .

4 0

3 years ago