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Alborosie
3 years ago
13

How is centripetal force related to circular motion?

Physics
1 answer:
Trava [24]3 years ago
3 0

Answer:

Circular motion requires a"centripetal" force. Without a centripetal force, an object cannot travel in circular motion. 

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Discuss how a photon (aka the light particle) can be affected by gravity despite being massless.
Over [174]

Explanation:

Light is clearly affected by gravity, just think about a black hole, but light supposedly has no mass and gravity only affects objects with mass. On the other hand, if light does have mass then doesn't mass become infinitely larger the closer to the speed of light an object travels.

4 0
3 years ago
How do you find displacement when all you have is time with no velocity, and then in order to find velocity you have to have dis
saw5 [17]
If you really have nothing else but time, then you can't. There must be some other shred of information. Search around. Look under rocks.
3 0
4 years ago
Calculate how far ahead of the drop zone a pilot would have needed to drop humanitarian aid packages if the delivery occurred at
ozzi

Answer:

S = 11488.42 m

Explanation:

Given,

The speed of the jet, v = 0.74 Mach

                                     = 253.82 m/s

The altitude of the jet, h = 10000 m

Since the jet is travelling horizontally, the vertical component of velocity Vy = 0

The equation for a projectile projected from a height h is given by,

                                  S = Vx [Vy + √(Vy² +2gh)] / g

Since Vy = 0

                                   S = Vx √(Vy² +2gh) / g

                                       = 253.82 x √(2 x 9.8 x 10000) / 9.8

                                       = 11488.42 m

Hence, the humanitarian aid package should be delivered ahead of distance, S = 11488.42 m

6 0
3 years ago
An experiment on the earth's magnetic field is being carried out 1.00 m from an electric cable. What is the maximum allowable cu
Whitepunk [10]

Answer:

The allowed current in the cable is 1.15 A.

Explanation:

Given that,

Distance = 1.00 m

Suppose the magnetic field is 2.3\times10^{-5}\ T and  if the experiment is to be accurate to 1.0 %

We need to calculate the current

Using formula of magnetic field

B=\dfrac{\mu_{0}I}{2\pi r}

I=\dfrac{B\times2\pi r}{\mu_{0}}

Put the value into the formula

I=\dfrac{2.3\times10^{-5}\times2\times\pi\times1.00}{4\pi\times10^{-7}}

I=115\ A

If the experiment is to be accurate to 1.0%

Then,

We need to calculate the allowed current in the cable

I'=(1.0%)\times I

I'=\dfrac{1.0}{100}\times115

I'=1.15\ A

Hence, The allowed current in the cable is 1.15 A.

4 0
3 years ago
PLEASE HELP ME!<br><br> How do you think the swarms affect local populations of humans?
Volgvan

Answer:

by temperature

Explanation:

cuz

5 0
3 years ago
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