Answer:
91.03 N
Explanation:
consider the way the forces are acting on the car , in the graph
assume the car is accelerating to the right
we can apply Newton's second law of motion (F = ma )
→ F = ma
Fpush + 107 = 1610 * 0.123
Fpush = 91.03 N
second guy is applying 91.03 N force on the car
The mechanical advantage is defined as the ratio between the load (output force) and the effort (input force):
for the ramp in our problem, the output force is 300 N, while the input force is 100 N, so the mechanical advantage of the ramp is:
Answer:
Speed is 1.962*10^-3m/s
Explanation:
Given that
Mass of proton==1.67*10^-27
Acceleration due to gravity (g)=9.81m/s^2
Angle of inclination A=90°
Charge (q)=1.6*10^-19
Magnetic field (B)=5*10^-5T
From lorentz force
It can be seen that
F=w =mg=qvBsinA
We're Velocity (v)=mg /qBsinA
V=1.67*10-27*9.81/1.6*10^-19*5*10^-5*sin90
V=1.962*10^-3m/s