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yKpoI14uk [10]
2 years ago
7

3. The electric field of a sinusoidal electromagnetic wave has an amplitude of 5.0 V/m. How much radiation energy passes through

a 1.5 m2 window perpendicular to the wave during one hour? a) 258 J b) 459 J c) 351 J d) 531 J e) 179 J
Physics
1 answer:
True [87]2 years ago
6 0

Answer:

e) 179 J

Explanation:

E_{o} = Magnitude of electric field = 5 V/m

A = Area of window = 1.5 m²

c = speed of electromagnetic wave = 3 x 10⁸ m/s

\Delta t = time interval = 1 h = 3600 sec

radiation energy is given as

U = (0.5)\epsilon _{o}E_{o}^{2}cA\Delta t

U = (0.5)(8.85\times 10^{-12})(5)^{2}(3\times 10^{8})(1.5)(3600)

U = 179 J

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IF YOU ANSWER THESE 4 QUESTIONS! I WILL GIVE YOU BRAINEST!!! 17 POINTS!!!
melisa1 [442]

Answer:

1.d

2.d

3.c

4.c

Okay, d & d, c & c. Iknow what you're thinking, I guessed. Nope! I just took a good look and chosed what I thought was the best answer

Explanation:

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4 0
2 years ago
A car moving at a speed of 36 km/h reaches the foot of a smooth
boyakko [2]

Answer:

d = 10.2 m

Explanation:

When the car travels up the inclined plane, its kinetic energy will be used to do the work in climbing up. So according to the law of conservation of energy, we can write that:

Kinetic\ Energy\ of\ the \ Car = Work\ Done\ while\ moving\ up\ the\ plane\\\frac{1}{2}mv^{2} = Fd

where,

m = mass of car

v = speed of car at the start of plane = (36 km/h)(1000 m/1 km)(1 h/3600 s)

v = 10 m/s

F = force on the car in direction of inclination = W Sin θ

W = weight of car = mg

θ = Angle of inclinition = 30°

d = distance covered up the ramp = ?

Therefore,

\frac{1}{2}mv^{2} = mgdSin\theta\\\frac{1}{2}v^{2} = gdSin\theta\\\frac{1}{2}(10\ m/s)^{2} = d(9.81\ m/s^{2}) Sin\ 30^{0}

<u>d = 10.2 m</u>

4 0
2 years ago
Tangential velocity 2. Parabolic pathway 3. Projectile 4. Centripetal acceleration 5. Centripetal force a. acceleration towards
Stels [109]

1. Tangential velocity:

<em>e) the instantaneous velocity of a body moving in a circular path.</em>

2. Parabolic pathway

<em>c. a curved path followed by projectiles</em>

3. Projectile

<em>d) an object projected through space, traveling in two dimensions, that accelerates vertically due to gravity.</em>

4. Centripetal acceleration

<em>a) acceleration towards the center caused by the centripetal force</em>

5. Centripetal force

<em>b) a force which keeps a body moving with a uniform speed along a circular path and is directed along the radius towards the center</em>

4 0
2 years ago
A 13.0-g wad of sticky clay is hurled horizontally at a 110-g wooden block initially at rest on a horizontal surface. The clay s
Alisiya [41]

Answer:

v_{ic}=92.53 m/s

Explanation:

We need to apply conservation of momentum and energy to solve this problem.

<u>Conservation of momentum</u>

p_{i}=p_{f}

m_{c}v_{ic}=(m_{c}+m_{w})V (1)

  • m(c) is the mass of stick clay
  • m(w) is the mass of the wooden block
  • v(ic) is the initial velocity of clay
  • V is the final velocity of the system clay plus wood.

<u>Conservation of total energy</u>

The change in kinetic energy is equal to the change in internal energy, in our case it would be the energy loss due to the friction force. Let's recall the definition of work, it is the dot product between force and displacement, Therefore:

\Delta E=W

\frac{1}{2}(m_{c}+m_{w})V^{2}=F_{friction}*d

\frac{1}{2}(m_{c}+m_{w})V^{2}=\mu (m_{c}+m_{w})gd

We can find V from this equation:

V=\sqrt{2\mu gd}=\sqrt{2*0.65*9.81*7.5}=9.78 m/s

Now, let's put V into the equation (1) and find v(ic)

v_{ic}=\frac{(m_{c}+m_{w})V}{m_{c}}=\frac{123*9.78}{13}=92.53 m/s

I hope it helps you!  

<u />

8 0
2 years ago
Melting, freezing, and boiling are _____________ changes. Question 3 options: A. compound
vfiekz [6]
Melting freezing and boiling are molecular changes


3 0
2 years ago
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