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Nata [24]
3 years ago
15

What is the total amount of heat required to completely melt 347 grams of ice at t's melting point

Chemistry
2 answers:
nikklg [1K]3 years ago
8 0
The answer is 116 000 J<span>
</span>
Ganezh [65]3 years ago
4 0

The amount of heat required to completely melt 347 g of ice is $$\boxed{115.898{\text{kJ}}}$$

Further explanation:

Latent heat  

The heat released or absorbed during the process of conversion physical state of a substance without altering the temperature is known as the latent heat.

When the physical state changes from the solid phase to liquid phase then the amount of heat absorbed in this process to completely convert the solid into liquid without altering the temperature is known as the latent heat fusion.

The formula to calculate heat absorbed from latent heat of fusion is,

$${\text{q}}={\text{m}}{{\text{H}}_{\text{f}}}$$           …… (1)

Here,

q is heat absorbed.

m is mass of substance.

${{\text{H}}_{\text{f}}}$ is latent heat of fusion.

The mass of given ice is 347 g.

The latent heat of fusion of ice is 334 J/g.

Substitute 347 g for m and 334 J/g for ${{\text{H}}_{\text{f}}}$ in equation (1) as follows:

$$\align{{\text{q}}&={\text{m}}{{\text{H}}_{\text{f}}}\cr&=\left( {347{\text{ g}}}\right)\left({334{\text{ J/g}}}\right)\cr&=115898{\text{ J}}\cr}$$

The heat required to completely melt 347 g of ice is 115898 J.

The heat required in kilojoule is as follows:

\begin{aligned}q&=(115898\text{ J})\left(\dfrac{1\text{ kJ}}{1000\text{ J}}\right)\\&=115.898\text{ kJ}\end

Learn more:

1. The difference between heat and temperature.:brainly.com/question/914750

2. Determine the process by which water enters into atmosphere?: <u>brainly.com/question/2037060</u>

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Thermodynamics

Keywords: Latent, Heat, fusion, Latent heat of fusion, temperature, ice, water, vapors, equilibrium, heat required, melting, heat release, heat absorbed, 115.898 kJ.

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3 years ago
A 11.97g sample of NaBr contains 22.34 % Na by mass. Considering the law of constant composition (definite proportions), how man
kap26 [50]
<h3>Answer:</h3>

2.125 g

<h3>Explanation:</h3>

We have;

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  • % composition by mass of Na in the sample is 22.34%

We are required to determine the mass of 9.51 g of a NaBr sample.

  • Based on the law of of constant composition, a given sample of a compound will always contain the sample percentage composition of a given element.

In this case,

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A sample of 9.51 g of NaBr will also contain 22.345 of Na by mass

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Mass of the element = (% composition of an element × mass of the compound) ÷ 100

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Mass of sodium = (22.34% × 9.51 g) ÷ 100

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