Question

what is the total amount of energy required to remove the most loosely bound electron from each atom in a mole of gaseous Ca

Answer 1

Answer:

589.8 kJ/mol

Explanation:

Let's consider the process in which the most loosely bound electron from each atom in a mole atom of gaseous calcium is removed.

Ca(g) + Energy ⇒ Ca¹⁺(g) + 1 e⁻

The energy involved in this process is known as First Ionization Energy. The First Ionization Energy for calcium is 589.8 kJ/mol.