what is the total amount of energy required to remove the most loosely bound electron from each atom in a mole of gaseous Ca
1 answer:
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Explanation:
For an isothermal process equation will be as follows.
W = nRT ln
It is given that mass is 10 kg/s or 10,000 g/s (as 1 kg = 1000 g). So, calculate number of moles of water as follows.
No. of moles =
=
= 555.55 mol/s
= 556 mol/s (approx)
As T = or (50 + 273.15) K = 323.15 K. Hence, putting the given values into the above formula as follows.
W = nRT ln[/tex]\frac{P_{1}}{P_{2}}[/tex]
=
=
= -3440193.809 J/s
Negative sign shows work is done by the pump. Since, 1 J = 0.001 kJ. Therefore, converting the calculated value into kJ as follows.
= 3440.193 kJ/s
= 3451 kJ/s (approx)
Thus, we can conclude that the pump work is 3451 kJ/s.