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3 years ago

what is the total amount of energy required to remove the most loosely bound electron from each atom in a mole of gaseous Ca

Chemistry

1 answer:

Temka [501]3 years ago

5 0

Answer:

589.8 kJ/mol

Explanation:

Let's consider the process in which <em>the most loosely bound electron from each atom in a mole atom of gaseous calcium is removed.</em>

Ca(g) + Energy ⇒ Ca¹⁺(g) + 1 e⁻

The energy involved in this process is known as First Ionization Energy. The First Ionization Energy for calcium is 589.8 kJ/mol.

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When the gases dihydrogen monosulfide and oxygen react, they form the gases sulfur dioxide and water vapor. Write the balanced c

Anna35 [415]

2(H2S) + 3(O2) -> 2(SO2) + 2(H2O)

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2 years ago

A chemist dissolves 867. mg of pure barium hydroxide in enough water to make up 170. mL of solution. Calculate the pH of the sol

Ilya [14]

Answer: The pH of the solution is 11.2

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in ml

moles of $Ba(OH)_2$ = $\frac{\text {given mass}}{\text {Molar mass}}=\frac{0.867g}{171g/mol}=0.00507mol$ (1g=1000mg)

Now put all the given values in the formula of molality, we get

$Molarity=\frac{0.00507\times 1000}{170}$

$Molarity=0.0298$

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

$pOH=-\log [OH^-]$

$Ba(OH)_2\rightarrow Ba^{2+}+2OH^{-}$

According to stoichiometry,

1 mole of $Ba(OH)_2$ gives 2 mole of $OH^-$

Thus 0.0298 moles of $Ba(OH)_2$ gives = $\frac{2}{1}\times 0.0298=0.0596$ moles of $OH^-$

Putting in the values:

$pOH=-\log[0.0596]=2.82$

$pH+pOH=14$

$pH=14-2.82$

$pH=11.2$

Thus the pH of the solution is 11.2

8 0

3 years ago

This is the process of sharing ideas, information, and opinions.

Ivanshal [37]

Communication will be the answer

6 0

3 years ago

How is an electrolytic cell different from a galvanic cell?

LenKa [72]

Answer:

Explanation:

4 0

3 years ago

How old is a bone if it now .3125 of C-14 when it originally had 80.0g of C-14

Taya2010 [7]

<h3>Answer:</h3>

42960 years

<h3>Explanation:</h3>

<u>We are given;</u>

Remaining mass of C-14 in a bone is 0.3125 g
Original mass of C-14 on the bone is 80.0 g
Half life of C-14 is 5370 years

We are required to determine the age of the bone;

Using the formula;

Remaining mass = Original mass × 0.5^n , where n is the number of half lives.

Therefore;

0.3125 g = 80.0 g × 0.5^n

3.90625 × 10^-3 = 0.5^n

Introducing logarithm on both sides;

log 3.90625 × 10^-3 = n log 0.5

Solving for n

n = log 3.90625 × 10^-3 ÷ log 0.5

= 8

Therefore, the number of half lives is 8
But, 1 half life is 5370 years
Therefore;

Age of the rock = 5370 years × 8

= 42960 years

Thus, the bone is 42960 years old

7 0

3 years ago