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vodomira [7]
3 years ago
5

what is the total amount of energy required to remove the most loosely bound electron from each atom in a mole of gaseous Ca

Chemistry
1 answer:
Temka [501]3 years ago
5 0

Answer:

589.8 kJ/mol

Explanation:

Let's consider the process in which <em>the most loosely bound electron from each atom in a mole atom of gaseous calcium is removed.</em>

Ca(g) + Energy ⇒ Ca¹⁺(g) + 1 e⁻

The energy involved in this process is known as First Ionization Energy. The First Ionization Energy for calcium is 589.8 kJ/mol.

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