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3 years ago

What is the strength of man made fiber

1 answer:

4 0

Characteristics and usage of Manmade Fibers
Luxurious feel and appearance.
A wide range of colors and lusters.
Excellent drapability and softness.
Relatively fast-drying.
Shrink-, moth-, and mildew-resistant.

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When a wave has λ=3 m and f=15 Hz, what is the speed of the wave?

Tamiku [17]

Wave speed = (wavelength) x (frequency)

Wave speed = (3 m) x (15 Hz)

<em>Wave speed = 45 m/s</em>

5 0

3 years ago

The distance of motion, or displacement, along a fault during an earthquake is known as:

k0ka [10]

<span>A fault slip is the distance of motion, or displacement, along a fault during an earthquake. They can be classified by their relation to the horizontal, for example, if the fault slip happens primarily vertically it is a dip slip.</span>

8 0

3 years ago

A train accelerates from a station with a = 1.841m/s ? Upon reaching a speed of 23.52m/s the train travels at a constant velocit

scZoUnD [109]

Answer:

63.29s

Explanation:

Firstly calculate the time taken to reach 23.52m/s

;use the formula...v = u + at

23.52 = 0 + 1.841t

then obtain...t = 12.78s

Then calculate the time for the last part of the journey...where the train slows down...

use the formula that is above...

0 = 23.52 - 2t...(negative for deceleration)

then obtain....t = 11.76s

Then we know that the total area under the graph of u against t..is equal to 1200m

For the first triangle(first part of the journey...where the train accelerates)

(23.52 × 12.78)÷2 = 150.3m

Then for the constant velocity part...a rectangle...

23.52 × f.....where f represents the time taken by the train having constant velocity.

...= 23.52fm

Then for the last part of the journey...the deceleration part..a triangle

(23.52 × 11.76)÷ 2 = 138.3m

Then....we add all the obtained distances and equate to 1200m so that we can obtain time (f)

138.3 + 150.3 + 23.52f = 1200

where f = 38.75s

Then total time for the whole journey of the train...

38.75 + 11.76 + 12.78

;Ans = 63.29s

3 0

3 years ago

Our textbook describes a common model for friction (both static and kinetic) in which the area of contact between interacting su

Mkey [24]

Contact area is not a factor of the amount of friction force acting between two bodies in contact, preventing rolling or sliding

Reasons:

Friction force is the product of the normal reaction and the coefficient of friction.

The coefficient of friction is higher in softer tires than hard tires which are required to be wider to reduce the pressure that can cause deformation withstood by hard tires.

The wide tires in drag racing cars can be thought of being made from the soft compound tire material having a higher coefficient of friction that increases the friction force.

Other advantages of wide tires are;

Increased traction

Shorter stopping distance

Learn more here:

brainly.com/question/17209968

7 0

3 years ago

A 0.4 kg ball is thrown straight up into the air with a velocity of 12.2 m/s. What maximum height will it reach?

AysviL [449]

Answer:

Maximum height is 7.59 m.

Explanation:

We have,

Mass of a ball is 0.4 kg

It is thrown straight up into the air with a velocity of 12.2 m/s.

It is required to find the maximum height reached by the ball.

Concept used : Law of conservation of energy.

Solution,

Here, the energy of the ball remains conserved. Let h is the maximum height reached by the ball such that,

$\dfrac{1}{2}mv^2=mgh\\\\h=\dfrac{v^2}{2g}\\\\h=\dfrac{(12.2)^2}{2\times 9.8}\\\\h=7.59\ m$

So, the maximum height reached by the ball is 7.59 m.

6 0

3 years ago

What is the strength of man made fiber​

What is the strength of man made fiber