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Afina-wow [57]
2 years ago
7

An ice cube and a scoop of table salt are left outside on a warm sunny day. explain why the ice cube melts and the salt does not

.
Chemistry
1 answer:
Anna11 [10]2 years ago
3 0

The melting point of ice is 0 degrees Celcius, which means it exists as a liquid for any temperatures above 0 degrees. The melting point of salt is approximately 800 degrees Celcius, which is way greater than the melting point of ice. This means that for temperatures below 800 degrees, salt exists as a solid.

The temperature of the area where they were placed we can assume was somewhere between 0 and 800 degrees, greater than the melting point of ice but less than the melting point of salt. This why the ice melted but the salt did not.

I hope this helps!

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What is 8.3 x 10^4 in standard form
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Explanation:

83,000 is 8.3x10^4 in standard form

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A box sitting on a floor. Maria and Sam push on the box in opposite direction. Maria pushes to the right using 95 N of Force and
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The equilibrium constant, k, for a redox reaction at 25° c is 7.3 × 107. what is the value of e° if the overall reaction transfe
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0.23 V.

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<em>∵ ΔG° = -RT lnK.</em>

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The measure of the attraction that an atom has for electrons involved in chemical bonds is known as:
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3 years ago
According to the following reaction, how many grams of potassium sulfate will be formed upon the complete reaction of 23.8 grams
Alexxandr [17]

<u>Answer:</u> The mass of potassium sulfate that can be produced is 73.88 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For KOH:</u>

Given mass of KOH = 23.8 g

Molar mass of KOH = 56.1 g/mol

Putting values in equation 1, we get:

\text{Moles of KOH}=\frac{23.8g}{56.1g/mol}=0.424mol

The chemical equation for the reaction of KOH and potassium hydrogen sulfate follows:

KHSO_4+KOH\rightarrow K_2SO_4+H_2O

As, potassium hydrogen sulfate is present in excess. It is considered as an excess reagent.

KOH is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of KOH produces 1 mole of potassium sulfate

So, 0.424 moles of KOH will produce = \frac{1}{1}\times 0.424=0.424moles of potassium sulfate

Now, calculating the mass of potassium sulfate from equation 1, we get:

Molar mass of potassium sulfate = 174.26 g/mol

Moles of potassium sulfate = 0.424 moles

Putting values in equation 1, we get:

0.424mol=\frac{\text{Mass of potassium sulfate}}{174.26g/mol}\\\\\text{Mass of potassium sulfate}=(0.424mol\times 174.26g/mol)=73.88g

Hence, the mass of potassium sulfate that can be produced is 73.88 grams

8 0
3 years ago
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