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3 years ago

50 POINTS*** Which of the following is not a correct chemical equation for a double displacement reaction?

Chemistry

2 answers:

Ira Lisetskai [31]3 years ago

7 0

Answer:-

B) CaCl2 + Li2CO3 --> CaCO3 + 2LiCl

D) 2MgI2 + Mn(SO3)2 ---> 2MgSO3 + MnI4

Explanation:-

For a reaction to be double displacement reaction there are two things we need to look for

1) There must be an interchange of the group of ions

2) The reactants must dissolve in water to release ions

In this question every option shows an interchange of ions. So we must use the second criteria to find out which one is not a double displacement reaction.

In case of B the two reactants are CaCl2 and Li2CO3.

Li2CO3 does not form ions on dissolving in water. It is because carbonate salts are not soluble in water.

Hence B) CaCl2 + Li2CO3 --> CaCO3 + 2LiCl is not a double displacement reaction.

In case of D the two reactants are MgI2 and Mn(SO3)2.

Mn(SO3)2 does not form ions on dissolving in water. It is because sulphite salt of metals except potassium and sodium are not soluble in water.

Hence D) 2MgI2 + Mn(SO3)2 ---> 2MgSO3 + MnI4 is not a double displacement reaction.

hammer [34]3 years ago

4 0

I mostly believe in between D and B beacuse K3po4 and caco3 is not an element equation

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Answer:

$2.14*10^{-3} mol$

Explanation:

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The trick is to remember to convert milligrams to grams because molar mass is normally presented in grams per mole

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3 years ago

Consider the following reaction where Kc = 1.80×10-2 at 698 K:2 HI (g) H2 (g) + I2 (g)A reaction mixture was found to contain 0.

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Answer:

Answer for the given statements: (1) T , (2) F , (3) T , (4) F , (5) F

Explanation:

At the given interval, concentration of HI = $\frac{0.304}{1}M=0.304M$

Concentration of $H_{2}$ = $\frac{5.07\times 10^{-2}}{1}M=5.07\times 10^{-2}M$

Concentration of $I_{2}$ = $\frac{4.57\times 10^{-2}}{1}M=4.57\times 10^{-2}M$

Reaction quotient, $Q_{c}$ , for this reaction = $\frac{[H_{2}][I_{2}]}{[HI]^{2}}$

species inside third bracket represents concentrations at the given interval.

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So, the reaction is not at equilibrium.

As $Q_{c}> K_{c}$ therefore reaction must run in reverse direction to reduce $Q_{c}$ and make it equal to $K_{c}$ . That means HI(g) must be produced and $H_{2}$ must be consumed.

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3 years ago

What will the charge oxidiation state be for boron

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Ira Lisetskai [31]

Answer:

4057.85 g/mol

Explanation:

Hello, the numerical procedure is shown in the attached file.

- In this case, since we don't have the density of the protein, we must assume that the volume of the solution is solely given by the benzene's volume, in order to obtain the moles of the solute (protein).

-Van't Hoff factor is assumed to be one.

Best regards.

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3 years ago

Determina el pH del café cuya concentración de H+ es de 0.00001M

lara31 [8.8K]

Answer:

Explanation:

Given parameters:

Hydrogen ion concentration = 0.00001M

Unknown:

pH of the solution =?

Solution:

The pH is used to estimate the degree of acidity or alkalinity of a solution. To solve for pH of any solution, we use the expression below;

pH = -log [H⁺]

[H⁺] is the hydrogen ion concentration

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3 years ago