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Aleonysh [2.5K]
3 years ago
9

How many centimeters are in 1 mile? Use the equalities 1 mile = 5280 feet; 1 foot = 12 inches; and 1 centimeter = 0.394 inches.

A. (5280 x 12 ∕ 0.394) cm B. 5280 ∕ (12 x 0.394) cm C. 5280 x 12 x 0.394 cm D. (5280 + 12 + 0.394) cm
Chemistry
2 answers:
Galina-37 [17]3 years ago
7 0
The answer is A which comes out to about 160812 cm
Alla [95]3 years ago
4 0

Answer:

A. \frac{5280*12}{0.394}cm

Explanation:

1. Take the quantity you want to convert:

1mile

2. Multiply by the first conversion factor:

1mile*\frac{5280feet}{1mile}

3. Apply the second conversion factor:

1mile*\frac{5280feet}{1mile}*\frac{12inches}{1foot}

4. Multiply by the third conversion factor:

1mile*\frac{5280feet}{1mile}*\frac{12inches}{1foot}*\frac{1centimeter}{0.394inches}

5. Multiply all the numerators and divide by denominators:

1mile*\frac{5280feet}{1mile}*\frac{12inches}{1foot}*\frac{1centimeter}{0.394inches}=\frac{5280*12}{0.394}cm

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<u>Answer:</u> The nuclear equations for the given process is written below.

<u>Explanation:</u>

The chemical equation for the bombardment of neutron to U-238 isotope follows:

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Beta decay is defined as the process in which neutrons get converted into an electron and a proton. The released electron is known as the beta particle.

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The chemical equation for the first beta decay process of _{92}^{239}\textrm{U} follows:

_{92}^{239}\textrm{U}\rightarrow _{93}^{239}\textrm{Np}+_{-1}^0\beta

The chemical equation for the second beta decay process of _{93}^{239}\textrm{Np} follows:

_{93}^{239}\textrm{Np}\rightarrow _{94}^{239}\textrm{Pu}+_{-1}^0\beta

Hence, the nuclear equations for the given process is written above.

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Answer: limiting reactant controls the amount of product formed in a chemical reaction.

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3 years ago
Which of the following atoms would be expected to be diamagnetic in the ground state?
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2 years ago
Cobalt-63 has a half-life of 5.3 years. If a pellet that has been in storage for 15.9 years contains 40.0g of Cobalt-63, how muc
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Answer:

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We can construct a table as follows:  

  No. of               Fraction         Mass

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      0        0              1

      1         5.3           ½

     2        10.6           ¼

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     4        21.2           ¹/₁₆

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This is one-eighth of the original mass.

The mass of the original sample was 8 × 40 g = 320 g

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3 years ago
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