Heart arteries lungs capillaries veins heart
Answer:
The six member ring and the position of the -OH group on the carbon (#4) identifies glucose from the -OH on C # 4 in a down projection in the Haworth structure). Fructose is recognized by having a five member ring and having six carbons, a hexose.
Answer:
1140 mmHg
Explanation:
1 atmosphere is 760 mmHg, so 1.5 atmospheres is ...
1.5×760 mmHg = 1140 mmHg
Honey<span> is a </span>homogeneous<span> mixture because it has the properties that define</span>homogeneous<span> solutions or mixtures.</span>
