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ASHA 777 [7]
2 years ago
13

What is the driving force between chemical reactions between elements

Chemistry
1 answer:
Maksim231197 [3]2 years ago
5 0

Answer:

energy Lol

Explanation:

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Consider the nuclear equation below. Superscript 235 subscript 92 upper U right arrow superscript 4 subscript 2 upper H e. What
coldgirl [10]

Answer:

\rm_{90}^{231}\text{Th}

Explanation:

The unbalanced nuclear equation is

\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} + X

Let's write X as a nuclear symbol.

\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} + _{Z}^{A}\text{X}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and of the subscripts must be the same on each side of the reaction arrow.

Then

235 = 4 + A , so A = 235 - 4 = 231, and

 92 = 2 + Z , so  Z =   92 - 2 =  90

And your nuclear equation becomes

\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} +\, _{90}^{231}\text{X}

Element 90 is thorium, so  

\rm X = _{90}^{231}\text{Th}

7 0
4 years ago
Which of the following NOT a principle of deep ecology, according to Arne Naess? All life has intrinsic value Environment must b
motikmotik

Answer:

On the picture are all principles cited on wikipedia.

Explanation:

So the answer is

1. Environment must be exploited to improve living standards

2. Flourishing human and nonhuman life depends on diversity of life forms

5 0
3 years ago
Why does blowing carbon dioxide gas into aqueous barium hydroxide reduce?
Oksana_A [137]
<span>If one chooses to blow carbon dioxide gas into aqueous barium hydroxide it will reduce. This happens because the ions become removed from the solution and in turn this decreases the conductivity of it.</span>
5 0
3 years ago
Read 2 more answers
Factors that remain the same throughout an experiment? What is the word
Jobisdone [24]
Their called constants
3 0
3 years ago
For the reaction, 2A + B → 3C, rate of disappearance of A is 0.3 M/s in a certain time interval.What is the average rate of appe
andrezito [222]

Answer:

E) rate of appearance of C = 0.45 M/s

rate of the reaction = 0.15 M/s

Explanation:

2A + B → 3C

Writing rate law for the reaction:

<u>Rate of reaction</u> = -\frac{1}{2}\frac{d[A]}{dt} = -\frac{d[B]}{dt} = \frac{1}{3}\frac{d[C]}{dt} → equation 1

Given that the rate of disappearance of A is 0.3 M/s

⇒ - \frac{d[A]}{dt} = 0.3 M/s

⇒Rate of reaction = - \frac{1}{2}\frac{d[A]}{dt} = \frac{1}{2}×0.3 M/s

⇒<u>Rate of reaction = 0.15 M/s</u>

From equation 1, \frac{d[C]}{dt} = - \frac{3}{2}\frac{d[A]}{dt} = \frac{3}{2}×0.3 M/s

⇒\frac{d[C]}{dt} = 0.45 M/s

or <u>the rate of appearance of C = 0.45 M/s</u>

7 0
3 years ago
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