First, we need to state the chemical equation for the combustion of PH3
And the mass of PH3 is 17.0 grams and we need to know the moles.
In the periodic table, the atomic mass of the P (phosphorus) is 31 and the atomic mass of the H (hydrogen) is 1.
So, you sum the mass of P to the mass of H multiplied by 3 and you obtain this:
With this data, we can search the moles of PH3:
Answer:
Rate of the reaction is 0.2593 M/s
-0.5186 M/s is the rate of the loss of ozone.
Explanation:
The rate of the reaction is defined as change in any one of the concentration of reactant or product per unit time.
Rate of formation of oxygen :
Rate of the reaction(R) =
Rate of formation of oxygen=3 × (R)
Rate of the reaction(R):
Rate of the reaction is 0.2593 M/s
Rate of disappearance of the ozone:
-0.5186 M/s is the rate of the loss of ozone.
The molecular weight of K2SO4 is 174.26 g/mole. The mass of K2SO4 required to make this solution is calculated in the following way.
550mL * (0.76mole/1000mL) * (174.26g/mole) = 72.84gram
<span>I hope this helps.</span>