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Nataliya [291]
3 years ago
9

Ionization energy and electron affinity both express the general attraction of an atom for

Chemistry
1 answer:
OleMash [197]3 years ago
4 0

Ionization energy is the energy required to remove an electron from an atom. Meanwhile, Electron affinity is the energy required to add an electron to an atom. So we can see that the two are opposite variables. However, they both refers to general attraction of an atom for “electron”.

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harkovskaia [24]
I think the answer is C , more dense
5 0
3 years ago
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How is the converging mirrors and diverging mirrors the same?
tia_tia [17]

Answer:

In converging mirrors light rays at the focus, while In diverging mirror it diverges the rays. Converging mirrors have positive focal length while Diverging mirrors have negative focal length. Converging mirrors form real,inverted and erect image while Diverging mirrors form erect images.

6 0
3 years ago
Someone explain it plz​
timofeeve [1]

Answer:

1). 1 mole of Carbon burnt in air

C + O2 →CO2

1 mole of carbon produces 1 mole of CO2 which is 44g of CO2

2). 1 mole of carbon is burnt in 16g of dioxygen

32g of O2 = 44g of CO2

1g of O2 = 44/32

CO2 (Dioxygen is limiting reagent)

16g of O2 = 4/32 × 16 = 22g of CO2 in one mole

3) 2 moles of Carbon burnt in 16g of dioxygen

16g of dioxygen is available, and thus it can combine with 0.5 mol of carbon to give 22g of CO2

4 0
3 years ago
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How much heat is transferred when during a reaction, 531 g of water increases from 22.7 ○C to 38.8 ○C?
vazorg [7]

Answer:

8.55 × 10³ cal

Explanation:

Step 1: Given and required data

  • Mass of water (m): 531 g
  • Specific heat of water (c): 1 cal/g.°C
  • Initial temperature: 22.7 °C
  • Final temperature: 38.8 °C

Step 2: Calculate the temperature change (ΔT)

ΔT = Final temperature - Initial temperature = 38.8 °C - 22.7 °C = 16.1 °C

Step 3: Calculate the heat required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 1 cal/g.°C × 531 g × 16.1 °C = 8.55 × 10³ cal

8 0
3 years ago
Calculate the silver ion concentration in a saturated solution of silver(I) sulfate (K sp = 1.4 × 10 –5). 1.5 × 10–2 M 1.4 × 10–
spin [16.1K]

Answer:

3.0x10⁻²M

Explanation:

Silver sulfate, Ag₂SO₄, has a product constant solubility equilbrium of:

Ag₂SO₄(s) ⇄ 2Ag⁺ + SO₄²⁻

When an excess of silver sulfate is added, some Ag₂SO₄ will react producing Ag⁺ and SO₄²⁻ until reach the equilbrium determined for the formula:

ksp = 1.4x10⁻⁵ = [Ag⁺]² [SO₄²⁻]

Assuming the Ag₂SO₄ that react until reach equilibrium is X, we can replace in Ksp expression:

1.4x10⁻⁵ = [Ag⁺]² [SO₄²⁻]

1.4x10⁻⁵ = [2X]² [X]

1.4x10⁻⁵ = 4X³

3.5x10⁻⁶ = X³

0.015 = X

As [Ag⁺] is 2X:

[Ag⁺] = 0.030 = 3.0x10⁻²M

The answer is:

<h3>3.0x10⁻²M</h3>
7 0
3 years ago
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