1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rainbow [258]
3 years ago
6

What is a work done on a body moving in a circular path ​

Physics
1 answer:
lesantik [10]3 years ago
4 0
Zero

This is because, when a body moves in a circular path, then the centripetal force acts along the radius of the circle, and it is at right angles to the motion of the body.
You might be interested in
A certain unbalanced force gives a 5kg object an acceleration of 15 m/s2. What would be the acceleration if the same force was a
stira [4]

Answer:

a2 = 2.5 m/s2

Explanation:

F1 = m1 a1 We use the same force so F1 = F2

= 5kg × 15m/s2 F2 = m2 a2

= 75N a2 is required

a2 = F2 / m2

= 75N / 30 kg

= 2.5 m/s2

7 0
4 years ago
Box A has a mass of 35.0kg and Box B has a mass of 20.0kg. What is the tension on
lions [1.4K]

EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEee

3 0
3 years ago
North Dakota Electric Company estimates its demand trend line​ (in millions of kilowatt​ hours) to​ be: D​ = 75.0 ​+ 0.45​Q, whe
Alborosie

Answer:

The demand forecast for winter is 96.36 millions KWH

The demand forecast for spring is 145.08 millions KWH

The demand forecast for summer is 169.89 millions KWH

The demand forecast for fall is 73.08 millions KWH

Explanation:

Given that,

The demand trend line​ is

D=(75.0+0.45Q)\times multiplicative\ seasonal\ factors

We need to calculate the demand forecast for winter

Using given formula

D=(75.0+0.45Q)\times multiplicative\ seasonal\ factors

Put the value into the formula

D=(75.0+0.45\times101)\times0.80

D=96.36\ millions\ KWH

We need to calculate the demand forecast for spring

Using given formula

D=(75.0+0.45Q)\times multiplicative\ seasonal\ factors

Put the value into the formula

D=(75.0+0.45\times102)\times1.20

D=145.08\ millions\ KWH

We need to calculate the demand forecast for summer

Using given formula

D=(75.0+0.45Q)\times multiplicative\ seasonal\ factors

Put the value into the formula

D=(75.0+0.45\times103)\times1.40

D=169.89\ millions KWH

We need to calculate the demand forecast for fall

Using given formula

D=(75.0+0.45Q)\times multiplicative\ seasonal\ factors

Put the value into the formula

D=(75.0+0.45\times104)\times0.60

D=73.08\ millions KWH

Hence, The demand forecast for winter is 96.36 millions KWH

The demand forecast for spring is 145.08 millions KWH

The demand forecast for summer is 169.89 millions KWH

The demand forecast for fall is 73.08 millions KWH

3 0
3 years ago
On your way to work about two hours after sunrise, you notice the moon setting. What phase is it in?
Naily [24]

The moon setting on your way to work about two hours after sunrise means it is in the gibbous phase.

<h3>What is Gibbous phase?</h3>

This phase of the moon involves its side facing the Earth appearing more than half-lit by the Sun, but is less than fully lit.

This phase occurs few hours after sunrise usually in the early morning which is why it is the most appropriate choice.


Read more about Gibbous phase here brainly.com/question/3729811

#SPJ1

6 0
2 years ago
You illuminate a slit of width 0.0675 mm with light of wavelength 711 nm and observe the resulting diffraction pattern on a scre
jasenka [17]
In the single-slit experiment, the displacement of the minima of the diffraction pattern on the screen is given by
y= \frac{n \lambda D}{a}
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern
\lambda is the light's wavelength
D is the distance of the screen from the slit
a is the width of the slit

In our problem, 
a=0.0675 mm=6.75 \cdot 10^{-5} m
\lambda=711 nm = 7.11 \cdot 10^{-7} m
D=2.21 m

And the distance of the first minimum (n=1) from the center of the pattern is
y= \frac{n \lambda D}{a}= \frac{(1) (7.11 \cdot 10^{-7} m)(2.21 m)}{6.75 \cdot 10^{-5} m}=2.33 \cdot 10^{-2} m =2.33 cm

The problem asks for the width of the pattern's central maximum. This will be equal to the distance between the first minimum on one side and the first minimum on the other side, so it will be equal to twice the distance we just found:
\Delta y_{max} = 2 y = 2\cdot 2.33 cm= 4.66 cm

4 0
4 years ago
Other questions:
  • Three particles are placed in the xy plane. A 50-g particle is located at (3, 4) m, and a 40-g particle is positioned at ( 2, 6)
    8·1 answer
  • A gas can compress and change shape easily. How do these properties relate to the motion of atoms in a gas?
    9·1 answer
  • Two objects are moving at equal speed along a level, frictionless surface. the second object has twice the mass of the first obj
    6·1 answer
  • A person on another planet shines a flashlight at you. The planet and the earth are both in the same reference frame and are not
    5·1 answer
  • The strong crystal structure of an ionic compound is one of the main reasons why ionic compounds have a __________ melting point
    12·1 answer
  • HELPPP ASAP!!!!!!
    11·1 answer
  • A 2.00-kg object is attached to a spring and placed on a frictionless, horizontal surface. A horizontal force of 20.0N is requir
    11·1 answer
  • Why is the pressure so high deep inside the outer planets?
    7·1 answer
  • The flow of electrons throughout a circuit is known as
    11·2 answers
  • What speed would an object have to travel to increase its mass by 50%?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!