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Over [174]
3 years ago
15

A mechanic needs to replace the motor for a merry-go-round. The merry-go-round should accelerate from rest to 1.5 rad/s in 7.0 s

. Consider the merry-go-round to be a uniform disk of radius 6.0 m and mass 25,000 kg. Suppose that it is supported by bearings that produce negligible friction torque.
Physics
1 answer:
marta [7]3 years ago
8 0

Answer

given,

initial speed of merry-go-round = 0 rad/s

final speed of merry-go-round = 1.5 rad/s

time = 7 s

Radius of the disk = 6 m

Mass of the merry-go-round = 25000 Kg

Moment of inertia of the disk

I = \dfrac{1}{2}MR^2

I = \dfrac{1}{2}\times 25000\times 6^2

   I = 450000 kg.m²

angular acceleration

\alpha = \dfrac{\omega_f-\omega_0}{t}

\alpha = \dfrac{1.5-0}{7}

\alpha =0.214\ rad/s^2

we know,

\tau= I \alpha

\tau= 450000\times 0.214

\tau=96300\ N.m

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Explanation:

Data provided:

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Mass of the firefighter = 756/9.8 = 77.14 Kg

Acceleration, a = 2.96 m/s²

a) In the absence of the pole the firefighter would have been moving down with an acceleration of 9.8 m/s (i.e the acceleration due to the gravity), but due to the presence of the pole the acceleration of the firefighter has been reduced. thus, a force is applied by the pole on the firefighter to reduce the acceleration.

therefore, we have

F = ma(net) = 77.14 × (9.8-2.96) = 527.65 N, Force applied is upwards.

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F = - 527.65 N

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