A large stone block is to be part of a harbour wall. The block is supported beneath the surface of the sea by a cable from a cra
ne. Fig 2.1 shows the block with its top face a distance h beneath the surface of the sea.
2 answers:
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Answer:
Explanation:
a = Orbital radius =
T = Orbital period = 23.21 hours
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
From Kepler's third law we get
From the given data the mass of Saturn is
Answer:
D. Because mass and energy are both conserved, the total amounts of mass and energy are the same before and after impact.
Explanation:
As we know that, the energy in motion is Kinetic Energy mathematically given as:
<u>Now, according to the law of conservation of energy:</u>
where:
mass of racquet and ball respectively and
are their respective initial velocities.
are the respective final velocities.
<u>Also the law of conservation of momentum is applicable in this case:</u>
In this case the velocity of the lighter mass will get increases in the final condition.
Answer:
principal stresses :б1 = 32.62mPa б2 = 31.38mPa
Max Shear stress : 16.31 mPa
Orientation of max principle plane = 44.43°
Orientation of minimum principal plane = 134.43°
Explanation:
Given data:
Torque = 50 N-m
weight = 80 kgs
half of weight is subjected to each leg
radius of bone = 10 mm = 0.010 m
<u>a) Determine the principal stresses and shear stress</u>
first calculate the max shear stress ( this will occur in the outermost element
= 16T / π*d^3 where : T = 50 , d = 0.020 m
hence max shear stress = 32 mPa
next determine compressive stress
= ( 40*g) / π/4*d^2 . where : d = 0.020 m , g = 9.81
hence compressive stress = 1.24 mPa
draw and calculate the radius of Mohr's circle
radius of Mohr's circle = 32.0060
Hence principal stresses = 32.0060 ± 0.62
б1 = 32.62mPa
б2 = 31.38mPa
attached below is the remaining part of the solution
