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Arturiano [62]
2 years ago
14

A large stone block is to be part of a harbour wall. The block is supported beneath the surface of the sea by a cable from a cra

ne. Fig 2.1 shows the block with its top face a distance h beneath the surface of the sea.

Physics
2 answers:
stich3 [128]2 years ago
4 0

Answer:

The top of the block has an area of 0.25m².

i) a Calculate the pressure on the top face of the block.

ii) The atmospheric pressure is 1.0 × 10⁵ Pa.

Calculate the pressure on the top face of the block due to the depth h of water.

iii) The density of sea water is 1020kg/m³.

Calculate the depth h.

lyudmila [28]2 years ago
3 0

Answer:

P=F/A, P is for pressure, F is for force, and A is for area, I can't really see half of the picture so I don't know the figures but just substitute them in and rearrange the equation if you have to. Good luck :))

Explanation:

You might be interested in
A box of mass m slides down an inclined plane that makes an angle of φ with the horizontal. if the coefficient of kinetic fricti
Schach [20]
In a force diagram set-up, we name the angle of inclination theta, g as the acceleration due to gravity. In this case, the forces acting on the box going down is the weight itself impeded by the friction between the box and the inclined plane.

The weight of the box is expressed as mg sin theta
The frictional force is expressed as the normal force times the coefficient of friction that is expressed as mu g cos theta.

By Newton's second law of motion,  F = ma = mg sin theta - mu g cos theta
Thus, a = g (sin theta - u cos theta

7 0
3 years ago
A car transports its passengers between 3 buildings. It moves from the first building to the second building, 4.76km away, in a
BigorU [14]

Answer:

1) a = 6.14 km

2) b = 4.69 km

Explanation:

Let the first building be A, second building be B and third building be C.

Now, bearing of A = 4.76 km in a direction 37° north of east

Bearing of B = 69° west of north

Bearing of C = 28° east of south

Thus if this 3 points form a triangle, we will have the following angles;

Angle at point A = 28 + (90 - 37) = 81°

Angle at point B = 28 + (90 - 69) = 49°

Angle at point C = 180 - (81 + 49) = 50°

Now, the distance between second and third building is "a" which is represented by BC in the triangle attached while the given distance of 4.76 represents side AB. Thus;

Using sine rule, we can find "a".

a/sin 81 = 4.76/sin 50

a = 6.14 km

B) distance between first and third building is AB in the triangle depicted by "b".

Similar to the first problem, we will use sine rule again.

b/sin49 = 4.76/sin 50

b = 4.69 km

8 0
3 years ago
If an earthquake occurred in Miami, Florida, then how long would it take for a seismic station in Seattle, Washington, to pick u
Juliette [100K]

0.017s

Explanation:

Given parameter

Distance = 5000km = 5 x 10⁶m

Unknown:

time taken = ?

Solution:

We use the normal speed equation to solve this problem as we take the speed of the wave to be 3 x 10⁸m/s.

   Speed = \frac{Distance }{Time taken}

   Inputting the parameters:

             Time taken = \frac{distance }{velocity of the wave}

  Time taken = \frac{ 5 000000}{3 00000000} = 0.017s

Learn more:

Earthquake brainly.com/question/11292835

#learnwithBrainly

8 0
2 years ago
A hiker walks 20.51 m at 33.16 degrees. What is the Y component of his displacement?
Serhud [2]

Answer:

<em>The y component of his displacement is 11.22 meters</em>

Explanation:

<u>Components of the displacement</u>

The displacement is a vector because it has a magnitude and a direction. Let's suppose a displacement has a magnitude r and a direction θ, measured with respect to the positive x-direction. The horizontal component of the displacement is calculated by:

x=r\cos\theta

The vertical component is calculated by:

y=r\sin\theta

The hiker has a displacement with magnitude r = 20.51 m at an angle of 33.16 degrees. Substituting in the above equation:

y=20.51\sin(33.16^\circ)

y=11.22\ m

The y component of his displacement is 11.22 meters

7 0
3 years ago
Question 4. A tuning fork ‘A’ produces 6 beats/sec with another fork ‘B’ of un-known frequency. On
8090 [49]

Clever problem.

We know that the beat frequency is the DIFFERENCE between the frequencies of the two tuning forks.  So if Fork-A is 256 Hz and the beat is      6 Hz, then Fork-B has to be EITHER 250 Hz OR 262 Hz.  But which one is it ?

Well, loading Fork-B with wax increases its mass and makes it vibrate SLOWER, and when that happens, the beat drops to 5 Hz.  That means that when Fork-B slowed down, its frequency got CLOSER to the frequency of Fork-A ... their DIFFERENCE dropped from 6 Hz to 5 Hz.

If slowing down Fork-B pushed it CLOSER to the frequency of Fork-A, then its natural frequency must be ABOVE Fork-A.

The natural frequency of Fork-B, after it gets cleaned up and returns to its normal condition, is 262 Hz.  While it was loaded with wax, it was 261 Hz.

4 0
3 years ago
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