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Arturiano [62]
2 years ago
14

A large stone block is to be part of a harbour wall. The block is supported beneath the surface of the sea by a cable from a cra

ne. Fig 2.1 shows the block with its top face a distance h beneath the surface of the sea.

Physics
2 answers:
stich3 [128]2 years ago
4 0

Answer:

The top of the block has an area of 0.25m².

i) a Calculate the pressure on the top face of the block.

ii) The atmospheric pressure is 1.0 × 10⁵ Pa.

Calculate the pressure on the top face of the block due to the depth h of water.

iii) The density of sea water is 1020kg/m³.

Calculate the depth h.

lyudmila [28]2 years ago
3 0

Answer:

P=F/A, P is for pressure, F is for force, and A is for area, I can't really see half of the picture so I don't know the figures but just substitute them in and rearrange the equation if you have to. Good luck :))

Explanation:

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iragen [17]

Answer:

The frequency of the oscillations in terms of fo will be f2=fo/3

E xplanation:

T= 2pie\frac sqrt {m}{k}

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⇒f2=fo\3

Here frequency f is inversely poportional to square root of mass m.

so the value of remainder of frequency f2 and fo is equal to 1:3.

⇒\frac{f2} {f1} = \frac sqrt{m1}[m2}

⇒\frac{f2}{fo} = 1:3

⇒f2=\frac{fo} {3}

6 0
3 years ago
What is the velocity of an object that has a momentum of 4,000 kg-m/s and a mass of 115 kg? Round to the nearest hundredth.
julia-pushkina [17]
<h2>Answer: 34.78 m/s</h2>

Explanation:

The momentum p is given by the following equation:

p=m.V   (1)

Where:

m is the mass of the object

V is the velocity of the object

Finding the velocity from (1):

V=\frac{p}{m}   (2)

V=\frac{4000kg.m/s}{115kg}  

<u>Finally:</u>

V=34.78m/s >>>This is the velocity of the object

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3 years ago
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