Answer:
The range of the 95% data (X) = 238.3 days < X < 289.9 days
Step-by-step explanation:
Given;
mean of the normal distribution, m = 264.1 days
standard deviation, d = 12.9 days
between two standard deviation below and above the mean is 96% of all the data.
two standard deviation below the mean = m - 2d
= 264.1 - 2(12.9)
= 238.3 days
two standard deviation above the mean = m + 2d
= 264.1 + 2(12.9)
= 289.9 days
The middle of the 95% of most pregnancies would be found in the following range;
238.3 days < X < 289.9 days
<u>Answer:</u>
<u>Step-by-step explanation:</u>
- 10 + 4.5m = 21.25
- => 4.5m = 21.25 - 10
- => 4.5m = 11.25
- => m = 11.25/4.5
- => m = 2.5
<u>Conclusion:</u>
Therefore, m = 2.5
Hoped this helped.

Answer:
Step-by-step explanation:
Answers are explained/Solved in the attach document.
Answer:
35/20
Step-by-step explanation:
20 divided by 4 = 5
so our multiple is 5
5 x 4 = 20
so we have to do the same to the numerator
5 x 7 = 35
Simplified= 1 3/5