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2 years ago

Help plzzzzzzzzzzzzzzzzz

Mathematics

1 answer:

beks73 [17]2 years ago

7 0

6^3

5•23

6/42 d equally what the vertex of the equations is

42 time 35 equals the nunally of the differnet vertex of the equation

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For every 60 students, three teachers are needed. Predict how many students 15 teachers can teach

Dmitrij [34]

Answer:

I think it's 45 students

Step-by-step explanation:

4 0

2 years ago

Write 8.54x10^3 in standard notation

suter [353]

Answer: The real number is 8540

Step-by-step explanation: 85.4 1000

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3 years ago

Which expression represents the ratio of the difference of the two means to Sidney's mean absolute deviation

prohojiy [21]

Answer:

The ratio of the difference of the two means to Sidney's mean absolute deviation = $\frac{4}{3.28}$ = 1.2195

Step-by-step explanation:

P.S - The exact question is -

Given - The means and mean absolute deviations of Sidney’s and Phil’s grades are shown in the table below.

Sidney’s Grades Phil’s Grades

Mean 82 78

Mean Absolute Deviation 3.28 3.96

To find - Which expression represents the ratio of the difference of the two means to Sidney’s mean absolute deviation?

Proof -

Given that Mean of Sidney Grades = 82

Mean of Phil's Grades = 78

So,

The difference of two means = 82 - 78 = 4

Also,

Given, Mean Absolute Deviation of Sydney = 3.28

Now,

The ratio of the difference of the two means to Sidney's mean absolute deviation = $\frac{4}{3.28}$ = 1.2195

4 0

2 years ago

Find the angle to the nearest degree. * sin-10.5166 1 31.1° 58.9° 0.5°

Mice21 [21]

Given:

The given inverse trigonometric term is:

$\sin^{-1}(0.5166)$

To find:

The value given inverse trigonometric term.

Solution:

We have,

$\sin^{-1}(0.5166)$

Using the calculator, we get

$\sin^{-1}(0.5166)=31.10446$

$\sin^{-1}(0.5166)\approx 31.1^{\circ}$

The value of given term is 31.1°.

Therefore, the correct option is B.

6 0

2 years ago

Which expression is equivalent to (x^4/3 x^2/3)^1/3?

KATRIN_1 [288]

Answer: $x^{\frac{2}{3} }$

Step-by-step explanation:

We have several properties of exponents in use here. The two that are used are:

$(x^{a})(x^{b}) = x^{a + b}$ (Exponents with the same base that are being multiplied together can have the exponents added)

$(x^{a})^{b} = x^{(a)(b)}$ (A base raised to a power, and then raised to another power means that you can multiply the exponents to get the same result as doing inside operations and then outside operations)

Let's apply it!

First, let's simplify what's inside the parenthesis.

$x^{\frac{4}{3} } x^{\frac{2}{3} }$ (Remember, they have the same base of "x", so we can add the exponents)

$x^{\frac{4}{3} + \frac{2}{3} }$ = $x^{\frac{6}{3} }$ = $x^{2}$

Now we have $(x^{2})^{\frac{1}{3} }$ . Let's use the second rule.

$(x^{2})^{\frac{1}{3} }$ = $x^{\frac{2}{3} }$

Hope this helps! :^)

7 0

3 years ago