Answer:
option d.......................
Answer: All options (I, II, III, IV, V)
Explanation: The answer is all options because they never reach equilibrium or intersect at a region as the both decrease at the same rate.
More positive ions shows acidic whereas more negative ions indicates basic solution.
<h3>Which charge show acidic solution?</h3>
That side which has more positive charges is considered as acidic solution while on the other hand, that region where negative charges are present in large number as compared to positive charges is considered as basic or alkaline solution.
So we can conclude that more positive ions shows acidic whereas more negative ions indicates basic solution.
Learn more about charge here: brainly.com/question/25923373
#SPJ1
The more particles (ions or molecules) that you can put into solution, the lower the freezing point.
the answer is E. 2.0 M nacl
Answer:
Explanation:
(NH4)3 PO4 +NaOH arrow Na3PO4 +3NH3 +3H2O
Start by seeing what happens with the Na. You need 3 on the left, so put a 3 in front of NaOH
(NH4)3 PO4 +3NaOH arrow Na3PO4 +3NH3 +3H2O Next work with the nitrogens. YOu have 3 on the left and 3 on the right, so they are OK. Next Go to the stray oxygens.
You have 3 on left in (NaOH) and three on the right in 3H2O so they are fine as well. The last thing you should look at are hydrogens.
There are 12 + 3 on the left which is 15. There are 9 (in 3NH3) and 6 more in the water. They seem fine.
Why didn't I do something with the PO4^(-3)? The reason is a deliberately stayed away from them and balanced everything else. Since they were untouched with 1 on the left and 1 on the right, they are balanced.
Species Na H O N PO4
Left 3 15 3 3 1
Right 3 15 3 3 1
