Boyle's law p1V1=p2V2
p2=(p1V1)/V2
p2=(205*10^3 Pa * 4*10^-3 m^3 ) / (12*10^-3 m^3)
p2= 68333 Pa
Firstly, a balanced equation has to be written for the production of ammonia (NH₃) from hydrogen gas (H₂) and nitrogen gas (N₂):
N₂ + 3H₂ → 2NH₃
Now, the mole ratio of N₂ : NH₃ is 1 : 2 based on the coefficients of the balanced equation.
If the moles of N₂ = 2.5 moles
then the moles of NH₃ produced = 2.5 mol × 2
= 5 mol
Thus, the moles of ammonia produced when 2.5 mol of nitrogen gas is combined with excess hydrogen gas is 5 mol.
There are approximately 160 grams in 1 mol of Fe2O3 molecules. Therefore, there would be 79/160= 0.49375 mols of Fe2O3 molecules in 79 grams. There are 5 atoms in total for each molecule of Fe2O3, therefore 79/160 * 5 = 79/32 = 2.46875 mols of atoms.
An acid is deemed strong if it can readily or easy "donate" a proton (H+) to the other ions in the solutions. Also, to donate or lose the proton or H+, the acid must dissociate (split into ions) in the solution. The more it can readily dissociate, the stronger the acid is.
