Answer:
7
Step-by-step explanation:
7 =2 hx x e
Answer:
305.78 in2
Step-by-step explanation:
The rocket has two parts: one is a cylinder and the other is a cone.
To find the total volume of the rocket, we need to find firstly the volume of each part.
The cylinder has a radius of 2 inches and a height of 2*12 + 5 - 7 = 22 inches, so its volume is:
V1 = pi * r^2 * h = pi * 2^2 * 22 = 276.46 in2
The cone has a radius of 2 inches and a height of 7 inches, so its volume is:
V2 = (1/3) * pi * r^2 * h = (1/3) * pi * 2^2 * 7 = 29.32 in2
Then, we have that the volume of the rocket is:
V = V1 + V2 = 276.46 + 29.32 = 305.78 in2
Answer: The required length of the segment AA' is 11 units.
Step-by-step explanation: Given that the point A(5, 11) is reflected across the X-axis.
We are to find the length of the segment AA'.
We know that
if a point (x, y) is reflected across X-axis, then its co-ordinates becomes (x, -y).
So, after reflection, the co-ordinates of the point A(5, 11) becomes A'(5, -11).
Now, we have the following distance formula :
The DISTANCE between two points P(a, b) and Q(c, d) gives the length of the segment PQ as follows :

Therefore, the length of the segment AA' is given by

Thus, the required length of the segment AA' is 11 units.
Addition: 93 can be added six times to determine the total
and division can be used to check your answer since it's the inverse operation of multiplication...take your solution of 558 and divide it by 6 (or 93) to see if 93 times six equals 558
The answer would be approximately 9 inches but the real number is 9.42 So B is the answer. I hope this helped ^^