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Feliz [49]
3 years ago
13

What mass of sodium hydroxide must be heated in order to produce 4.5 g of water?

Chemistry
1 answer:
inysia [295]3 years ago
5 0

Answer:

10 g

Explanation:

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What is 4.07 cm x 2.3cm, rounded to the correct number of significant figures
Tom [10]

Answer: 9.4cm^2

Explanation:

8 0
3 years ago
What is the pH of a solution in which [H 3O +] = 3.8 × 10 -8 M?
7nadin3 [17]

Answer:

<h3>The answer is 7.42 </h3>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ { H_3O}^{+}]

From the question we have

pH =  -  log(3.8 \times  {10}^{ - 8} )  \\  = 7.420216...

We have the final answer as

<h3>7.42 </h3>

Hope this helps you

4 0
3 years ago
PLZZ HELP ASAPPPJKSOWLSOWOLWKSKW
Minchanka [31]
I’m pretty the answer would be continental slope. :)
I really hope this helps.
4 0
3 years ago
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You drop a ball from a height of 2.0 m, and it bounces back to a height of 1.6 m. (a) what fraction of its initial energy is los
sweet [91]

Answer : Part a) Fraction of energy lost : 20 %

Part b) Speed before and after bounce = 6.3 m/s and 5.6 m/s

Part c) Energy is lost as thermal energy .

Part A) Fraction of energy lost during bouncing :

The energy possessed by any object when present at any height is potential energy . The formula of potential energy is given as :

PE = mgh

where PE = potential energy

,m = mass pf object , g = gravitational acceleration and h = height

Given : Initial height , h₁ = 2 m final height , h₂ = 1.6 m

Initial potential energy : m * g* h ₁

Final potential energy = m* g* h₂

Energy lost = Initial PE - Final PE

= ( mgh₁ - mgh2 )

Fraction of energy lost : \frac{energy lost}{initial energy}=\frac{mgh1 - mgh2}{mgh1}

Plugging value in above formula and taking " mg " common =>

Fraction of energy lost = \frac{mg(h1-h2)}{mg (h1)} * 100

= \frac{(h1-h2)}{h1}  * 100

= \frac{(2 - 1.6) }{2}  * 100

Fraction of energy lost = 20%

---------------------------------------------------------------------------------------------------

Part B ) Speed of ball just before and after the bounce.

Speed of ball before the bounce :

The potential energy gets converted to kinetic energy when it fall from height of 2m , so

Potential energy = kinetic energy

mgh₁ = \frac{1}{2} m v²

or v ² = 2gh₁

Given : g = 9.8 m/s² h= 2 m

v² = 2 * 9.8 m/s² * 2 m = 39.2 m²/s²

v = 6.3 m/s

Speed of ball after bounce :

Potential energy = kinetic energy

mgh₂ = \frac{1}{2} m v²

or v² = 2gh₂

= 2 * 9.8 m/s² * 1.6 m = 31.36 m²/s²

v = 5.6 m/s

---------------------------------------------------------------------------------------------

Part C) The energy lost due to friction. When the ball touches the ground , there occur friction force between the surface of ground and ball , due to which energy is lost as thermal energy .

5 0
3 years ago
Read 2 more answers
The pressure in an engine cylinder increases from 7.6 atm to 13 atm as the gas is compressed from 0.50 L to 0.10 L. What is the
REY [17]
T k = 15 + 273 = 288 K

4.6 / 13 => 0.353 atm

0.50 / 0.10 => 5 L

<span>(15 + 273) K x (13 atm / 7.6 atm) x (0.50 L / 0.10 L) 
</span>
<span>= </span>2463.15 K

<span>hope this helps!</span>
8 0
3 years ago
Read 2 more answers
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