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Dafna1 [17]
3 years ago
13

How carbon dioxide prepared in lab?

Chemistry
1 answer:
Nana76 [90]3 years ago
7 0

Explanation:

In laboratory, carbon dioxide is not obtained from the air, carbon dioxide is prepared from carbonates by adding acids to the carbonates. In this experiment carbon dioxide is prepared by the reaction of marble with hydrochloric acid.

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The 54.9-g sample of the compound X2O7 contains 33.6 g of oxygen atoms. What is the molar mass of element X?
vazorg [7]
Mass of X₂O₇ = 54,9g

2x + 33,6g = 54,9g
2x = 54,9g - 33,6g
2x = 21,3g  | :2
x = 10,65g/mol
7 0
3 years ago
Read 2 more answers
g modenr vacuum pumps make it easy to attain pressures of the order of in the laboratory. at a preasusure of 6.75 atm and an ord
Ratling [72]

Answer:

Number of molecules = 1.8267×10^20

Explanation:

From the question, we can deuced that the gases behave ideally, the we can make use of the ideal gas equation, which is expressed below;

PV = nRT

where

P =pressure

V =volume

n = the number of moles

R is the gas constant equal to 0.0821 L·atm/mol·K

T is the absolute temperature

Given:

P = 6.75 atm;

T = 290.0 k,

; V = 1.07 cm³ = 0.001 L

( 6.75 atm)(0.00107 L) = n(0.0821 L·atm/mol·K)(290K)

n = 3.0335167*10^-4 moles

But there are 6.022×10²³ molecules in 1 mole,

Number of molecules = 1.8267×10^20

7 0
3 years ago
So I have an F in science, and everything is due today. Am I going to fail 9th grade because I didn't pass that class?
Elis [28]

Answer:

i dk how ur school works, but you'll most likely have to take that science again to get the credits u need to graduate

Explanation:

3 0
3 years ago
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What is the volume of an object with a mass of 220g and a desnisty of 55cm3?
dmitriy555 [2]
Volume=Mass over density. V= 220/55. V=4cm^3
7 0
3 years ago
A solution contains 22.4 g glucose (C6H12O6 ) dissolved in 0.500 L of water. What is the molality of the solution
Shalnov [3]

Answer:

Molality is 0.25 m

Explanation:

Molality → Moles of solute / kg of solvent

We need the moles of solute → 0.124 moles

22.4 g . 1 mol / 180 g = 0.124 moles

We need the mass of solvent in kg. We determine the mass of solvent with density.

Density = Mass / Volume

Mass = Density . volume → 1 g/mL . 500 mL = 500 g

If we convert the mass in g to kg → 500 g . 1kg / 1000 g = 0.5 kg

In conclussion, molality → 0.124 mol / 0.5 kg = 0.25 m

8 0
3 years ago
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