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tatuchka [14]
3 years ago
13

Which of the following describes scientists?

Chemistry
2 answers:
Serga [27]3 years ago
4 0

Answer:

C. People with perfect understanding of science

Explanation:

Similar personalities, different backgrounds, and only one perspective are just traits of people.

Perfect understanding of science is relating to a scientist. Scientists have high knowledge of science.

jasenka [17]3 years ago
3 0

Answer:C.people with perfect understanding of science.

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If the caffeine concentration in a particular brand of soda is 3.55 mg/oz, drinking how many cans of soda would be lethal? Assum
monitta

Answer:

The answer to your question is: 234.7 cans

Explanation:

data

caffeine concentration = 3.55 mg/oz

10.0 g of caffeine is lethal

there are 12 oz of caffeine in a can

Then

                    3.55 mg ----------------- 1 oz

                      x    mg  -----------------12 oz (in a can)

x = 42.6 mg of caffeine in a can

Convert it to grams 42,6 mg = 0.0426 g of caffeine in a can

Finally

            0.0426 g of caffeine ------------------  1 can

            10           g of caffeine -----------------    x

x = 10 x 1/0.0436 = 234.7 cans

6 0
3 years ago
The pKa of the α‑carboxyl group of serine is 2.21 , and the pKa of its α‑amino group is 9.15 . Calculate the average net charge
sleet_krkn [62]

Answer:

Net charge in serine at pH equal to 8.30 is "0"

Explanation:

  • At pH > pK_{a}, carboxyl group exists as -CO_{2}^{-} (charged)
  • At pH < pK_{a}, carboxyl group exists as -COOH (neutral)
  • At pH > pK_{a}, amino group exists as -NH_{2} (neutral)
  • At pH < pK_{a}, amino group exists as -NH_{3}^{+} (charged)
  • So, at pH = 8.30, both carboxyl and amino group exists in charged state.
  • Net charge in serine at pH equal to 8.30 is "0".
  • Structure of serine at pH equal to 8.30 has been shown below.

8 0
3 years ago
Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch
Inessa [10]

Answer:

The answer is "\bold{4.97 \times 10^{-2}}"

Explanation:

Please find the complete question in the attached file.

Equation:

2SO_2+O_2  \leftrightharpoons 2SO_3

at t=0 3.3   \ \ \ \ \ \ \ \ \ \ 0.79

at equilibrium 3.3-p \ \ \ \ \ \ \ \ \ \ 0.79 - \frac{P}{2} \ \ \ \ \ \ \ \ \ \ \ \ P

p= 0.47 \ \ atm\\\\SO_2=3.3-0.47 = 2.83 \ \ atm\\\\O_2= 0.74 -\frac{0.47}{2}=0.74-0.235=0.555 \ atm\\\\K_P=\frac{[PSO_3]^2}{[PSO_2]^2[PO_2]}\\\\

     =\frac{0.47^2}{2.83^2\times 0.555}\\\\=4.97 \times 10^{-2}

8 0
3 years ago
Is sulfur a metal, nonmetal, metalloid, or noble gas?
Blababa [14]
Sulfer is a nonmetal
6 0
2 years ago
Lead forms two compounds with oxygen. One contains 2.98g of lead and 0.461g of oxygen. The other contains 9.89g of lead and 0.76
aliina [53]

The given question is incomplete, the complete question is:

Lead forms two compounds with oxygen. One contains 2.98g of lead and 0.461g of oxygen. The other contains 9.89g of lead and 0.763g of oxygen. For a given mass of oxygen, what is the lowest whole-number mass ratio of lead in the two compounds that combines with a given mass of oxygen?

Answer:

The lowest whole-number mass ratio in the two compounds is 1:2.

Explanation:

There is a need to find the mole ratio between lead and oxygen atoms in order to find the whole-number mass ratio of lead in the two compounds. In the first compound, the given mass of lead is 2.98 grams, the molar mass of lead is 207.2 gram per mole.  

The no. of moles can be determined by using the formula,  

moles = mass/molecular mass

moles = 2.98 g/207.2 g/mol

= 0.0144 moles

The mass of oxygen in the compound I is 0.461 grams, the molecular mass of oxygen is 16 gram per mol.  

moles = 0.461 g /16 g/mol

= 0.0288 moles

The ratio between the lead and oxygen in the compound I is 0.0144/0.0288 = 1:2

On the other hand, in the compound II, the mass of lead given is 9.89 grams, therefore, the moles of lead in compound II is,  

moles = 9.89 g / 207.2 g/mol

= 0.0477 moles

The mass of oxygen given in compound II is 0.763 grams, the moles of oxygen present in the compound II is,  

moles = 0.763 g / 16 g

= 0.0477 moles

The ratio between the lead and oxygen in the compound II is, 0.0477 moles lead /0.0477 moles oxygen = 1:1

Hence, of the two compounds, the lowest ratio is found in the compound I, that is, 1:2.  

4 0
3 years ago
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