The gravitational potential energy of the rock is:
490 J at 50 m
196 J at 20 m
9.8 J at 1 m
Explanation:
The gravitational potential energy (GPE) of an object is the energy possessed by the object due to its position in the gravitational field.
For an object near the Earth's surface, the GPE is given by
![GPE=mgh](https://tex.z-dn.net/?f=GPE%3Dmgh)
where
m is the mass of the object
is the acceleration of gravity at Earth's surface
h is the heigth of the object relative to the ground
For the rock in this problem,
m = 1 kg
So its GPE at h = 50 m is
![GPE(50)=(1)(9.8)(50)=490 J](https://tex.z-dn.net/?f=GPE%2850%29%3D%281%29%289.8%29%2850%29%3D490%20J)
The GPE at h = 20 m is
![GPE(20)=(1)(9.8)(20)=196 J](https://tex.z-dn.net/?f=GPE%2820%29%3D%281%29%289.8%29%2820%29%3D196%20J)
While the GPE at h = 1 m is
![GPE(1)=(1)(9.8)(1)=9.8 J](https://tex.z-dn.net/?f=GPE%281%29%3D%281%29%289.8%29%281%29%3D9.8%20J)
Learn more about gravitational potential energy:
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