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Anestetic [448]
3 years ago
5

A 75.0-kg ice skater moving at 10.0 m/s crashes into a stationary skater of equal mass. After the collision, the two skaters mov

e as a unit at 5.00 m/s. Suppose the average force a skater can experience without breaking a bone is 4 500 N. If the impact time is 0.100 s, does a bone break?
Physics
1 answer:
Ksenya-84 [330]3 years ago
4 0

Answer:

Explanation:

Momentum change for either skater is mΔv = 75.0(5.0) = 375 kg•m/s

As a change in momentum is equal to an impulse

375 = FΔt

F = 375/0.100 = 3750 N

As 3750 N < 4500 N no bones are broken.

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Answer:

<h2>4.6 m/s²</h2>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

<h3>a =  \frac{v - u}{t}  \\</h3>

where

v is the final velocity

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Since the body is from rest u = 0

From the question we have

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We have the final answer as

<h3>4.6 m/s²</h3>

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2 years ago
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cluponka [151]

Answer:

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Explanation:

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ii) Since we have all the values all that's left is to plug them into the equation

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0.5* (s.45/1000)*(4^2)

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Hope this was useful! :)

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battery

Explanation:

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