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emmasim [6.3K]
3 years ago
7

What are 3-D glasses made of?

Physics
1 answer:
Firlakuza [10]3 years ago
5 0
Plastic is what they are made of
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give an example of one living and one non-living thing that uses the force of buoyancy to function. explain how they work.
zaharov [31]

Answer:

the biotic one is a human in water and they flaot because of the air in our lungs and the abiotic one is a swimming buoys are filled with foam and foam floats

Explanation:

...

4 0
1 year ago
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What is its maximum altitude above the ground? The answer is the maximum height above the ground
Kisachek [45]

Answer:

Maximum altitude above the ground = 1,540,224 m = 1540.2 km

Explanation:

Using the equations of motion

u = initial velocity of the projectile = 5.5 km/s = 5500 m/s

v = final velocity of the projectile at maximum height reached = 0 m/s

g = acceleration due to gravity = (GM/R²) (from the gravitational law)

g = (6.674 × 10⁻¹¹ × 5.97 × 10²⁴)/(6370000²)

g = -9.82 m/s² (minus because of the direction in which it is directed)

y = vertical distance covered by the projectile = ?

v² = u² + 2gy

0² = 5500² + 2(-9.82)(y)

19.64y = 5500²

y = 1,540,224 m = 1540.2 km

Hope this Helps!!!

3 0
3 years ago
The force of gravity on Mercury is less than the Earth because:
Vinvika [58]
Mercury has less mass than earth. So the answer is B
7 0
3 years ago
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A 2-lb slider is propelled upward at A along the fixed curved bar which lies in a vertical plane. If the slider is observed to h
timofeeve [1]

To develop this problem it is necessary to apply the concepts given in the balance of forces for the tangential force and the centripetal force. An easy way to detail this problem is through a free body diagram that describes the behavior of the body and the forces to which it is subject.

PART A) Normal Force.

F_n = \frac{mv^2}{r}

N+mgcos\theta = \frac{mv^2}{r}

Here,

Normal reaction of the ring is N and velocity of the ring is v

N+mgcos\theta = \frac{mv^2}{r}

N+Wcos\theta = \frac{W}{g} (\frac{v^2}{r})

N+2cos30\° = \frac{2}{32.2}*\frac{10^2}{2}

N = 1.374lb

PART B) Acceleration

F_t = ma_t

-mgsin\theta = ma_t

-W sin\theta = \frac{W}{g} a_t

-2Sin30\° = (\frac{2}{32.2})a_t

a_T = -16.10ft/s^2

Negative symbol indicates deceleration.

<em>NOTE: For the problem, the graph in which the turning radius and the angle of suspension was specified was not supplied. A graphic that matches the description given by the problem is attached.</em>

8 0
3 years ago
What speed would a proton need to achieve in order to circle Earth 1790 km above the magnetic equator, where the Earth's mag- ne
irinina [24]

Answer:

The velocity is 31.25 m/s and direction is toward west.

Explanation:

Given that,

Distance h= 1790 km = 1.790\times10^{6}\ m

Magnetic field B=4\times10^{-8}\ T

Mass of proton m=1.673\times10^{-21}\ Kg

Radius of earth R =6.38\times10^{6}\ m

Radius of orbit r=R+h

r=6.38\times10^{6}+1.790\times10^{6}

r=8170000\ m

We need to calculate the speed

Using formula of magnetic field

Bvq=\dfrac{mv^2}{r}

v=\dfrac{Bqr}{m}

Put the value into the formula

v=\dfrac{4\times10^{-8}\times1.6\times10^{-19}\times8170000}{1.673\times10^{-21}}

v=31.25\ m/s

Hence, The velocity is 31.25 m/s and direction is toward west.

6 0
3 years ago
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