4 years ago

Evaporation only occurs at the surface of a liquid

Physics

1 answer:

Veseljchak [2.6K]4 years ago

8 0

yes

evaporation starts on the surface

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Two strong magnets were brought close to each other. They were repelling each other. Explain what must have happened.

r-ruslan [8.4K]

When two magnets are brought together, the opposite poles will attract one another, but the like poles will repel one another. This is similar to electric charges. Like charges repel, and unlike charges attract.

pls. mark brainliest am. dyning for it

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3 years ago

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A student at another university repeats the experiment you did in lab. Her target ball is 0.860 m above the floor when it is in

dexar [7]

Answer:

K = 0.076 J

Explanation:

The height of the target, h = 0.860 m

The mass of the steel ball, m = 0.0120 kg

Distance moved, d = 1.50 m

We need to find the kinetic energy (in joules) of the target ball just after it is struck. Let t is the time taken by the ball to reach the ground.

$h=ut+\dfrac{1}{2}at^2\\\\t=\sqrt{\dfrac{2h}{g}}$

Put all the values,

$t=\sqrt{\dfrac{2\times 0.860 }{9.8}} \\\\=0.418\ s$

The velocity of the ball is :

$v=\dfrac{1.5}{0.418}\\\\= $$3.58\ m/s$

The kinetic energy of the ball is :

$K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 0.0120\times 3.58^2\\\\=0.076\ J$

So, the required kinetic energy is 0.076 J.

6 0

3 years ago

Want brainly?? Answer this question correctly and I got you.

matrenka [14]

Answer:

divergent

Explanation:

That is when two plate boundaries slide apart

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3 years ago

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A book is sliding to a stop while moving across the classroom floor

Margarita [4]

Answer:

can you please elaborate the question

Explanation:

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3 years ago

Now instead a 3-mw laser of wavelength λ = 760 nm is directed into the interferometer (with the mirror m1 at the displacement ca

slavikrds [6]

power received will always remain same and does not depends on the distance

it will be same as the power of source

$P = 3 mW$

now the energy released by one photon is given as

$E = \frac{hc}{\lambda}$

$E = \frac{6.6* 10^{-34}* 3 * 10^8}{760 * 10^{-9}}$

$E = 2.6 * 10^{-19} J$

now let say N photons per second released

$N * 2.6 * 10^{-19} = 3 * 10^{-3}$

$N = 1.15* 10^{16} per\: second$

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3 years ago