Evaporation only occurs at the surface of a liquid

What are some of the objects found in space and their characteristics?

RideAnS [48]

Answer:

meteor

Explanation:

big rock or metal maybe

6 0

3 years ago

The velocity of the wind relative to the water is crucial to sailboats. Suppose a sailboat is in an ocean current that has a vel

Brilliant_brown [7]

Answer:

Explanation:

We shall write the velocities given in vector form to make the solution easy.

The velocity of water with respect to earth that is waV(e) makes 30 degree with north or 60 degree with east so in vector form

waV(e) = 2.2 cos 60 i + 2.2 sin 60 j

waV(e) = 1.1 i + 1.9 j

Similarly , velocity of wind with respect to earth that is wiV(e) , is making 50 degree with west or - ve of x axes so we cal write it in vector form as follows

wiV(e) = - 4.5 cos 50 i - 4.5 sin 50 j

wiV(e) = - 2.89 i - 3.45 j

Now we have to calculate velocity of wind with respect to water that is

wiVwa

wiV( wa) = wiV ( e)+ eV(wa)

= wiV( e)- waV(e)

- 2.89 i - 3.45 j - 1.1 i - 1.9 j

= - 3.99 i - 5.35 j

Magnitude of this relative velocity

D² = 3.99² + 5.35²

d = 6.67 m /s

6 0

3 years ago

How will you charge a metal sphere by the process of induction?

zzz [600]

<span>A Conducting Sphere Is On Top Of An Insulating Stand. So A Negatively Charged Tube Is Brought Near The Neutral Sphere Then It Forces Electron Movement From The Left To The Right Side Of The Sphere. Once Touched By The Ground, The Electrons Leave The Sphere. When The Tube Is Moved Away, There's An Overall Positive Charge Left On The Sphere.</span>

3 0

3 years ago

A proton moves through a region containing a uniform electric field given by E with arrow = 54.0 ĵ V/m and a uniform magnetic fi

madreJ [45]

Answer:

acceleration is 9.58 × $10^{7}$ (- 14 ĵ + 51 k ) m/s

Explanation:

given data

uniform electric field E = 54.0 ĵ V/m

uniform magnetic field B = (0.200 î + 0.300 ĵ + 0.400 k) T

velocity v = 170 î m/s.

to find out

acceleration

solution

we know magnetic force for proton is

i.e = e (velocity × uniform magnetic field)

magnetic force = e (170 î × (0.200 î + 0.300 ĵ + 0.400 k) )

magnetic force = e (- 68 ĵ + 51 k ) ..................1

and now for electric force for proton i.e

= uniform electric field × e ĵ

electric force = e (54 ĵ ) ............2

so net force will be add magnetic force + electric force

from equation 1 and 2

e (- 68 ĵ + 51 k ) + e (54 ĵ )

e (- 14 ĵ + 51 k )

so the acceleration (a) for proton will be

net force = mass × acceleration

a = e (- 14 ĵ + 51 k ) / 1.6 $10^{-19}$ / 1.67 × $10^{-27}$

acceleration = 9.58 × $10^{7}$ (- 14 ĵ + 51 k ) m/s

7 0

3 years ago

The average bulk resistivity of the human body (apart from surface resistance of the skin) is about 5.0 Ω⋅m. The conducting path

Varvara68 [4.7K]

Answer:

A) R = 1019.11 Ω

B) V = 101.91 V

Explanation:

a) The resistance is given by the formula;

R = ρL/A

Where;

ρ is bulk density = 5.0 Ωm

L is length of cylinder = 1.6m

A is area = (π/4)D² = (π/4) x 0.1² = 0.007854 m²

Plugging in the relevant values, we obtain ;

R = (5 Ωm x 1.6m)/(0.007854 m²)

R = 1019.11 Ω

b) potential difference is given by;

V = RI

Thus, plugging in relevant values, we obtain;

V = 1019.11 Ω ∙ 0.1A

V = 101.91 V

7 0

3 years ago