Answer:
The speed of the galaxy relative to the Earth is
.
Explanation:
We have,
(a) Wavelength emitted by light at distant galaxy is 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 nm. It can be seen that the wavelength of light reduces as it reaches Earth. It is called Red shift. As per Doppler's effect, we can say that the galaxy is receding from the Earth.
(b) Let v is the speed of the galaxy relative to the Earth. It can be given by :

So, the speed of the galaxy relative to the Earth is
.
This is false. Even though the first part is true, the second isn't because morals and values are simply widely accepted opinions that most humans have, and you can't test opinions with the scientific method, only facts!
Answer:
The tension on the string is
Explanation:
From the question we are told that
The mass of the rock is 
The density of the rock is
Generally the volume of the rock is mathematically evaluated as

substituting values


The volume of the rock immersed in water is
substituting values


mass of water been displaced by the this volume is
According to Archimedes principle
=> 

The weight of the water displace is



The actual weight of the rock is

The tension on the string is
substituting values
Answer:
H_w = 2.129 m
Explanation:
given,
Width of the weir, B = 1.2 m
Depth of the upstream weir, y = 2.5 m
Discharge, Q = 0.5 m³/s
Weir coefficient, C_w = 1.84 m
Now, calculating the water head over the weir




now, level of weir on the channel
H_w = y - H
H_w = 2.5 - 0.371
H_w = 2.129 m
Height at which weir should place is equal to 2.129 m.
Answer:
the energy from the sun travel to earth the answer is A .through the radiation