Answer: Option (1) is the correct answer.
Explanation:
The vertical distance between crest or trough from the origin or equilibrium point is known as amplitude of a wave.
In the given pictures, a wave that shows maximum height from the origin will have the maximum amplitude. Whereas the wave that shows minimum height from the origin will have the smallest amplitude.
Thus, we can conclude that waves shown in option 1 will have the smallest amplitude.
Answer:B
Explanation:
Given
Distance of astronaut From asteroid x is 
Distance of astronaut From asteroid Y is 
Suppose M,M_x,M_y be the masses of Astronaut , asteroid X and Y
If the astronaut is in equilibrium then net gravitational force on it is zero
cancel out the common terms we get
Answer:
1.35×10⁻⁷ m
37.278 mi/My
Explanation:
Speed of the tectonic plate= 6 cm/yr
Converting to seconds
So in one second it will move
In 71 seconds
The tectonic plate will move 1.35×10⁻⁵ cm or 1.35×10⁻⁷ m
Convert to mi/My
1 cm = 6.213×10⁻⁶ mi
1 M = 10⁶ years
Speed of the tectonic plate is 37.278 mi/My
Answer:
a) T = 608.22 N
b) T = 608.22 N
c) T = 682.62 N
d) T = 533.82 N
Explanation:
Given that the mass of gymnast is m = 62.0 kg
Acceleration due to gravity is g = 9.81 m/s²
Thus; The weight of the gymnast is acting downwards and tension in the string acting upwards.
So;
To calculate the tension T in the rope if the gymnast hangs motionless on the rope; we have;
T = mg
= (62.0 kg)(9.81 m/s²)
= 608.22 N
When the gymnast climbs the rope at a constant rate tension in the string is
= (62.0 kg)(9.81 m/s²)
= 608.22 N
When the gymnast climbs up the rope with an upward acceleration of magnitude
a = 1.2 m/s²
the tension in the string is T - mg = ma (Since acceleration a is upwards)
T = ma + mg
= m (a + g )
= (62.0 kg)(9.81 m/s² + 1.2 m/s²)
= (62.0 kg) (11.01 m/s²)
= 682.62 N
When the gymnast climbs up the rope with an downward acceleration of magnitude
a = 1.2 m/s² the tension in the string is mg - T = ma (Since acceleration a is downwards)
T = mg - ma
= m (g - a )
= (62.0 kg)(9.81 m/s² - 1.2 m/s²)
= (62.0 kg)(8.61 m/s²)
= 533.82 N
<span>A particle released during the fission of uranium-235 is a "Neutron"</span>
