540 nonlillion
thats a 540 followed by 30 0's
<span>Calculate the velocity of the Earth in its orbit around the Sun. Page 3. 2. M = 1.99 × 10 kg (mass of the Sun) ... Orbital radius of the Earth: 149.6 × 10 km = 1 AU. 6 ... that are especially stable have a better chance to survive than atoms whose ... in the Sun occurs only in its core and that the density of the core is greater than the ...</span><span>
</span>
Answer:
1.22 m/s
1.76 m/s
0
1.46 m/s
Explanation:
*in the first part i have taken 26 m as in the part above it is mentioned distance is 26 m.
= Displacement of the first run = 26 m
= Displacement of the second run = 26 m
= Time taken on the first run = 20.7 s
= Time taken on the second run = 14.8 s
Velocity is given by
Average velocity of the first run is 1.22 m/s
Average velocity of the first run is 1.76 m/s
Displacement for the round trip is 0 as she started and ended at the same point so her average velocity for the round trip is 0 m/s.
Average speed is given by
The average speed for the round trip is 1.46 m/s.
They need to loose an electron to become more stable. This completes a valence shell.