Dissolving 25.00 g cucl2 in enough water to make 250 ml of solution gives a solution concentration equal to
1 answer:
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The solution has a concentration equal to 10% m/v
There are several units of concentration. The exercise doesn't specify which one should be used, so we'll use the most simple one which is percentage mass/volume. To calculate percentage mass/volume we'll only need the mass of the solute (in this case CuCl₂ and the volume of solution. The formula is the following one:
Have a nice day!
The solution has a concentration equal to 10% m/v
There are several units of concentration. The exercise doesn't specify which one should be used, so we'll use the most simple one which is percentage mass/volume. To calculate percentage mass/volume we'll only need the mass of the solute (in this case CuCl₂ and the volume of solution. The formula is the following one:
Have a nice day!
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Answer:
8.32 s⁻¹
Explanation:
Given that:
The concentration of myosin = 25 pmol/L
R_max = 208 pmol/L/s
The objective is to determine the turnover number of the enzyme molecule myosin, which has a single active site.
In a single active site of enzyme is known to be a region where there is binding of between substrate molecules, thereafter undergoing chemical reaction.
The turnover number of the enzyme is said to be the number of these substrate molecule which binds together are being converted into products.
The turnover number of the enzyme molecule of myosin can be calculated by the expression:
⇒
= 8.32 s⁻¹