The answer for this issue is:
The chemical equation is: HBz + H2O <- - > H3O+ + Bz-
Ka = 6.4X10^-5 = [H3O+][Bz-]/[HBz]
Let x = [H3O+] = [Bz-], and [HBz] = 0.5 - x.
Accept that x is little contrasted with 0.5 M. At that point,
Ka = 6.4X10^-5 = x^2/0.5
x = [H3O+] = 5.6X10^-3 M
pH = 2.25
(x is without a doubt little contrasted with 0.5, so the presumption above was OK to make)
I think because its the only one to be liquid at normal temperatures.
Did u mean mass of potassium nitrate or the mass of nitrogen in potassium nitrate
- <em>NH</em> <em> </em><em>at </em><em>5</em><em> </em><em>atm</em>
³
<h2><em>hope</em><em> it</em><em> helps</em><em>!</em></h2>
<em>correct</em><em> me</em><em> if</em><em> </em><em>I'm</em><em> </em><em>wrong</em>
