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podryga [215]
3 years ago
7

The gas in an aerosol can is at a pressure of 3.16 atm at 32.2°C. What would the gas pressure in the can be at 22.9°C?

Chemistry
1 answer:
olasank [31]3 years ago
5 0

Answer:

The pressure of the gas would be 3.06 atm

Explanation:

Amonton's law states that the pressure is directly proportional to the absolute temperature of a gas under constant volume. The equation is:

P1 / T1 = P2 / T2

<em>Where P1 is the initial pressure = 3.16atm</em>

<em>T1 is initial absolute temperature = 273.15 + 32.2°C = 305.35K</em>

<em>P2 is our incognite</em>

<em>And T2 is = 273.15 + 22.9°C = 296.05K</em>

<em />

Replacing:

3.16atm / 305.35K = P2 / 296.05K

3.06 atm = P2

<h3>The pressure of the gas would be 3.06 atm</h3>
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yawa3891 [41]

Answer:

a. 2 HgO(s) ⇒ 2 Hg(l) + O₂(g)

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Explanation:

Step 1: Write the balanced equation

2 HgO(s) ⇒ 2 Hg(l) + O₂(g)

Step 2: Convert 130.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15

K = 130.0°C + 273.15

K = 403.2 K

Step 3: Calculate the moles of O₂

We will use the ideal gas equation.

P × V = n × R × T

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The molar ratio of HgO to O₂ is 2:1. The moles of HgO required are 2/1 × 2.21 × 10⁻³ mol = 4.42 × 10⁻³ mol.

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The molar mass of HgO is 216.59 g/mol.

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