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podryga [215]
3 years ago
7

The gas in an aerosol can is at a pressure of 3.16 atm at 32.2°C. What would the gas pressure in the can be at 22.9°C?

Chemistry
1 answer:
olasank [31]3 years ago
5 0

Answer:

The pressure of the gas would be 3.06 atm

Explanation:

Amonton's law states that the pressure is directly proportional to the absolute temperature of a gas under constant volume. The equation is:

P1 / T1 = P2 / T2

<em>Where P1 is the initial pressure = 3.16atm</em>

<em>T1 is initial absolute temperature = 273.15 + 32.2°C = 305.35K</em>

<em>P2 is our incognite</em>

<em>And T2 is = 273.15 + 22.9°C = 296.05K</em>

<em />

Replacing:

3.16atm / 305.35K = P2 / 296.05K

3.06 atm = P2

<h3>The pressure of the gas would be 3.06 atm</h3>
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The superheated water vapor is at 15 MPa and 350°C. The gas constant, the critical pressure, and the critical temperature of wat
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Answer:

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Explanation:

Given:

P = 15 MPa

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T = 350 °C

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4 0
3 years ago
Suppose that 25,0 mL of a gas at 725 mmHg and 298K is converted to
posledela

The new volume : 21.85 ml

<h3>Further explanation</h3>

Given

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P1=725 mmHg

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Always subtract the smaller number from the greater one. 
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A simple way to know if it's polar or nonpolar is to draw the lewis dot structure, and use VSEPR. 

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