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podryga [215]
3 years ago
7

The gas in an aerosol can is at a pressure of 3.16 atm at 32.2°C. What would the gas pressure in the can be at 22.9°C?

Chemistry
1 answer:
olasank [31]3 years ago
5 0

Answer:

The pressure of the gas would be 3.06 atm

Explanation:

Amonton's law states that the pressure is directly proportional to the absolute temperature of a gas under constant volume. The equation is:

P1 / T1 = P2 / T2

<em>Where P1 is the initial pressure = 3.16atm</em>

<em>T1 is initial absolute temperature = 273.15 + 32.2°C = 305.35K</em>

<em>P2 is our incognite</em>

<em>And T2 is = 273.15 + 22.9°C = 296.05K</em>

<em />

Replacing:

3.16atm / 305.35K = P2 / 296.05K

3.06 atm = P2

<h3>The pressure of the gas would be 3.06 atm</h3>
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Pls help ty so much!
Nitella [24]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:mass = 11.42 \:\: grams

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \: Q = ms\Delta T

  • \textsf{Q = heat evolved/absorbed = 501 J}

  • \textsf{m = mass in gram = ?}

  • \textsf{s = specific heat = 0.45}

  • \textsf{ΔT = change in temp = 120 - 22.5 =97.5°C}

\large\textsf{Find m : }

\qquad \tt \rightarrow \: 501 = m \sdot(0.45) \sdot(97.5)

\qquad \tt \rightarrow \:  501 = m \sdot43.875

\qquad \tt \rightarrow \: m =  \dfrac{501}{43.875}

\qquad \tt \rightarrow \: m  \approx11.42 \:  \: g

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

4 0
1 year ago
7) Muscles work to lift a bone in your arm by contracts and relaxes to<br><br><br>help please <br>​
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Answer:

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Explanation:

yeah, hope it helps a little. :)

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