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2 years ago

The gas in an aerosol can is at a pressure of 3.16 atm at 32.2°C. What would the gas pressure in the can be at 22.9°C?

Chemistry

1 answer:

olasank [31]2 years ago

5 0

Answer:

The pressure of the gas would be 3.06 atm

Explanation:

Amonton's law states that the pressure is directly proportional to the absolute temperature of a gas under constant volume. The equation is:

P1 / T1 = P2 / T2

Where P1 is the initial pressure = 3.16atm

T1 is initial absolute temperature = 273.15 + 32.2°C = 305.35K

P2 is our incognite

And T2 is = 273.15 + 22.9°C = 296.05K

Replacing:

3.16atm / 305.35K = P2 / 296.05K

3.06 atm = P2

<h3>The pressure of the gas would be 3.06 atm</h3>

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A sample of gas occupies 0.04 L at 150 K. What volume does that sample occupy at 300 K?

Natalka [10]

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2 years ago

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White raven [17]

Answer:

The number of neutrons is entirely dependent on the Mass number of the particular atom. The standard mass for potassium is 39.

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1 year ago

Read 2 more answers

1. A 5.05 g sample of quartz (SiO2) contains 2.36 g of silicon. What are the percentages of silicon

hammer [34]

Answer: B) 46.7% Si and 53.3% O

Explanation:

To calculate the mass percent of element in a given compound, we use the formula:

$\text{Mass percent of element}=\frac{\text{Mass of element}}{\text{total mass}}\times 100\%$

Mass of quartz $(SiO_2)$ = 5.05 g

Mass of silicon = 2.36 g

Mass of oxygen = Mass of quartz $(SiO_2)$ - mass of silicon = 5.05g - 2.36 g = 2.69 g

$\text{Mass percent of silicon}=\frac{\text{Mass of silicon}}{\text{total mass of quartz}}\times 100=\frac{2.36}{5.05}\times 100=46.7\%$

$\text{Mass percent of oxygen}=\frac{\text{Mass of oxygen}}{\text{total mass of quartz}}\times 100=\frac{2.69}{5.05}\times 100=53.3\%$

Thus the percentages of silicon and oxygen in quartz are B) 46.7% Si and 53.3% O

6 0

2 years ago

If 3 moles of H2 react with two moles of o2 what is limiting reactant

Dominik [7]

H₂ is the limiting reactant.

Explanation:

H₂ reacts with O₂

The reaction would be

2H₂ + O₂ → 2H₂O

According to the balanced equation, 2 moles of H₂ reacts with 1 mole of O₂ to form 2 moles of H₂O.

The ratio of usage of H₂ and O₂ is 2 : 1 respectively

If 3 moles of H₂ and 2 moles of O₂ are present then:

3 moles of H₂ would require 1.5 moles of O₂ ( 2 : 1 of H₂ and O₂ )

Out of 2 moles of O₂, 1.5 moles would be used and 0.5 mole would be in excess.

Therefore, H₂ is the limiting reactant as the number of moles of H₂ are not enough to use all the O₂.

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2 years ago

A 37.2 g sample of copper at 99.8 °C is carefully placed into an insulated container containing 188 g of water at 18.5 °C. Calcu

klasskru [66]

Answer:

T₂ = 19.95°C

Explanation:

From the law of conservation of energy:

$Heat\ Lost\ by\ Copper = Heat\ Gained\ by\ Water\\m_cC_c\Delta T_c = m_wC_w\Delta T_w$

where,

mc = mass of copper = 37.2 g

Cc = specific heat of copper = 0.385 J/g.°C

mw = mass of water = 188 g

Cw = specific heat of water = 4.184 J/g.°C

ΔTc = Change in temperature of copper = 99.8°C - T₂

ΔTw = Change in temperature of water = T₂ - 18.5°C

T₂ = Final Temperature at Equilibrium = ?

Therefore,

$(37.2\ g)(0.385\ J/g.^oC)(99.8\ ^oC-T_2)=(188\ g)(4.184\ J/g.^oC)(T_2-18.5\ ^oC)\\99.8\ ^oC-T_2 = \frac{(188\ g)(4.184\ J/g.^oC)}{(37.2\ g)(0.385\ J/g.^oC)}(T_2-18.5\ ^oC)\\\\99.8\ ^oC-T_2 = (54.92) (T_2-18.5\ ^oC)\\54.92T_2+T_2 = 99.8\ ^oC + 1016.02\ ^oC\\\\T_2 = \frac{1115.82\ ^oC}{55.92}$

T₂ = 19.95°C

6 0

2 years ago