Here, we are going to calculate the mass % of C in the mixture.
What is a Mixture?
A mixture is composed of one or more pure substances in varying composition. There are two types of mixtures: heterogeneous and homogeneous. Heterogeneous mixtures have visually distinguishable components, while homogeneous mixtures appear uniform throughout.
Given that,
The mass % of CO =35.0% =35.0 g in 100 g mixture
The mass % of CO2 = 65% =65 g in 100 g mixture
Therefore,
The mass of C from CO = 15.007 g C
Similarly,
The mass of C from CO2 = 17.738 g C
Thus, the total mass of C = 15.007 g+17.738 g =32.745 g
Therefore,
The mass % of C= 32.745% =32.7%
Thus, the mass % of C in the mixture is 32.7%
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Answer:
1. 2 M
2. 2 M
Explanation:
1. Determination of the final concentration.
Initial Volume (V₁) = 2 L
Initial concentration (C₁) = 6 M
Final volume (V₂) = 6 L
Final concentration (C₂) =?
The final concentration can be obtained as follow:
C₁V₁ = C₂V₂
6 × 2 = C₂ × 6
12 = C₂ × 6
Divide both side by 6
C₂ = 12 / 6
C₂ = 2 M
Therefore, the final concentration of the solution is 2 M
2. Determination of the final concentration.
Initial Volume (V₁) = 0.5 L
Initial concentration (C₁) = 12 M
Final volume (V₂) = 3 L
Final concentration (C₂) =?
The final concentration can be obtained as follow:
C₁V₁ = C₂V₂
12 × 0.5 = C₂ × 3
6 = C₂ × 3
Divide both side by 3
C₂ = 6 / 3
C₂ = 2 M
Therefore, the final concentration of the solution is 2 M
The last question depends on the scientific method.
Scientific Method
1. Make an observation of what u are testing 2. Form a question about ur observations. 3. Make a hypothesis 4. Conduct your experiment 5. Record information and results.
The first question depends what you will need to use first for the experiment.
First put the choices,and the answer is <span>(10^-3L/1mL)^3 is the correct answer.</span>
