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m_a_m_a [10]
3 years ago
14

Which change occurs when a barium atom loses two electrons?(1) It becomes a negative ion and its radius decreases.(2) It becomes

a negative ion and its radius increases.(3) It becomes a positive ion and its radius decreases.(4) It becomes a positive ion and its radius increases.
Chemistry
2 answers:
OleMash [197]3 years ago
6 0

Answer:

The correct answer is option 3, It becomes a positive ion and its radius decreases

Explanation:

As per the Octet rule, Barium has 2 electrons in its outermost shell. When it loses the two electron it gains two positive charge i.e Ba2+. As the barium loses the two electron from its outermost shell, the outermost shell becomes vacant and thus is no more considered as a part of atomic geometry of the barium atom and since the outermost shell is considered negligible the radius of barium atom reduces automatically.  

Tcecarenko [31]3 years ago
5 0
<h2>Changes Occurs when a Barium Atom - Option 3  </h2>

When a barium atom loses two electrons it becomes a positive ion and its radius decreases. Barium (Ba) has atomic number 56 so it has 2 electrons in first shell of an atom to become stable according to duplet rule. Then other 52 electrons revolve in the shells according to octet rules.

Another 2 electrons are in the outermost shell. To become stable electrons lose to form barium ions (Ba+2). Hence, by losing 2 electrons the outermost shell will be diminished so its radius decreases and by losing electrons it becomes positive ions.

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