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Mashutka [201]
3 years ago
6

What other substance containing sodium would be needed to make the buffer?

Chemistry
2 answers:
d1i1m1o1n [39]3 years ago
8 0
The other substance containing sodium would be expected to make the cushion is NaClO or the Sodium hypochlorite. It is for all intents and purposes and synthetically particular from chlorine. Sodium hypochlorite is much of the time utilized as a disinfectant or a blanching operator.
sergejj [24]3 years ago
3 0

\boxed{{\text{NaClO}}} would be needed to make the buffer.

Further explanation:

Buffer solution:

These solutions offer resistance to any changes in their pH if strong acid or base is added to them. Buffer solutions are basically aqueous solution consisting of weak acid and its conjugate base.

The alkalinity or acidity of any solution is governed by its pH. pH range varies from 0 to 14. Solutions that have pH less than 7 are acidic in nature, those with pH 7 are neutral and those with pH more than 7 are basic or alkaline in nature.

Categorization of buffer solutions:

Acidic buffer:

These solutions have pH less than 7 and are formed by weak acid and its conjugate base. For example mixture of acetic acid and sodium acetate form acidic buffer.

Basic buffer:

These solutions have pH more than 7 and are formed by weak base and its conjugate acid. For example mixture of ammonium chloride and ammonium hydroxide form basic or alkaline buffer.

Consider {\text{Cl}}{{\text{O}}^ - } as a base and its sodium salt becomes NaClO. {\text{Cl}}{{\text{O}}^ - } is strong base so its conjugate acid becomes weak. Since buffer is composed of aqueous solution of weak acid and its conjugate base, NaClO can be used to make buffer.

Learn more:

  1. The mass of ethylene glycol: brainly.com/question/4053884
  2. Basis of investigation for the scientists: brainly.com/question/158048

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Buffer solutions

Keywords: buffer solution, pH, NaClO, acidic buffer, basic buffer, 7, less than 7, more than 7, ClO-.

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Paraphin [41]
The  molarity   of solution  made  by  dissolving  15.20g  of i2  in 1.33 mol  of diethyl ether (CH3CH2)2O  is    =0.6M

   calculation

molarity  =moles of solute/  Kg of the  solvent

mole  of the solute  (i2)  =  mass /molar mass
the molar mass of i2 = 126.9 x2 = 253.8 g/mol

moles is therefore=  15.2 g/253.8 g/mol  =  0.06  moles


calculate the Kg of solvent  (CH3CH2)2O
mass =  moles  x  molar mass
molar mass  of  (CH3CH2)2O= 74 g/mol

mass  is therefore = 1.33 moles  x  74 g/mol =  98.42 grams
in Kg = 98.42 /1000 =0.09842  Kg

molarity  is therefore = 0.06/0.09842 = 0.6 M

3 0
3 years ago
A chemist dissolves 240mg of pure barium hydroxide in enough water to make up of solution. Calculate the pH of the solution. (Th
goblinko [34]

Answer:

pH = 12.22

Explanation:

<em>... To make up 170mL of solution... The temperature is 25°C...</em>

<em />

The dissolution of Barium Hydroxide, Ba(OH)₂ occurs as follows:

Ba(OH)₂ ⇄ Ba²⁺(aq) + 2OH⁻(aq)

<em>Where 1 mole of barium hydroxide produce 2 moles of hydroxide ion.</em>

<em />

To solve this question we need to convert mass of the hydroxide to moles with its molar mass. Twice these moles are moles of hydroxide ion (Based on the chemical equation). With moles of OH⁻ and the volume we can find [OH⁻] and [H⁺] using Kw. As pH = -log[H⁺], we can solve this problem:

<em>Moles Ba(OH)₂ molar mass: 171.34g/mol</em>

0.240g * (1mol / 171.34g) = 1.4x10⁻³ moles * 2 =

2.80x10⁻³ moles of OH⁻

<em>Molarity [OH⁻] and [H⁺]</em>

2.80x10⁻³ moles of OH⁻ / 0.170L = 0.01648M

As Kw at 25°C is 1x10⁻¹⁴:

Kw = 1x10⁻¹⁴ = [OH⁻] [H⁺]

[H⁺] = Kw / [OH⁻] = 1x10⁻¹⁴/0.01648M = 6.068x10⁻¹³M

<em>pH:</em>

pH = -log [H⁺]

pH = -log [6.068x10⁻¹³M]

<h3>pH = 12.22</h3>
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