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Mashutka [201]
3 years ago
6

What other substance containing sodium would be needed to make the buffer?

Chemistry
2 answers:
d1i1m1o1n [39]3 years ago
8 0
The other substance containing sodium would be expected to make the cushion is NaClO or the Sodium hypochlorite. It is for all intents and purposes and synthetically particular from chlorine. Sodium hypochlorite is much of the time utilized as a disinfectant or a blanching operator.
sergejj [24]3 years ago
3 0

\boxed{{\text{NaClO}}} would be needed to make the buffer.

Further explanation:

Buffer solution:

These solutions offer resistance to any changes in their pH if strong acid or base is added to them. Buffer solutions are basically aqueous solution consisting of weak acid and its conjugate base.

The alkalinity or acidity of any solution is governed by its pH. pH range varies from 0 to 14. Solutions that have pH less than 7 are acidic in nature, those with pH 7 are neutral and those with pH more than 7 are basic or alkaline in nature.

Categorization of buffer solutions:

Acidic buffer:

These solutions have pH less than 7 and are formed by weak acid and its conjugate base. For example mixture of acetic acid and sodium acetate form acidic buffer.

Basic buffer:

These solutions have pH more than 7 and are formed by weak base and its conjugate acid. For example mixture of ammonium chloride and ammonium hydroxide form basic or alkaline buffer.

Consider {\text{Cl}}{{\text{O}}^ - } as a base and its sodium salt becomes NaClO. {\text{Cl}}{{\text{O}}^ - } is strong base so its conjugate acid becomes weak. Since buffer is composed of aqueous solution of weak acid and its conjugate base, NaClO can be used to make buffer.

Learn more:

  1. The mass of ethylene glycol: brainly.com/question/4053884
  2. Basis of investigation for the scientists: brainly.com/question/158048

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Buffer solutions

Keywords: buffer solution, pH, NaClO, acidic buffer, basic buffer, 7, less than 7, more than 7, ClO-.

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Yakvenalex [24]
The balanced equation is:
2Na_3N-\ \textgreater \ 6Na + N_2

Then proceed with the following equations.


100g Na_3N*(\frac{1molNa_3N}{82.98gNa_3N})*(\frac {6mol Na}{2molNa_3N})*(\frac {22.99gNa}{1molNa})=83.12gNa

The answer is 83.12gNa.
7 0
3 years ago
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Choose the best statement of the octet rule from those listed below atoms lose 8 electrons to become valent atoms lose 8 electro
Mnenie [13.5K]

Answer:

atoms tend to react in order to gain 8 valence electrons

Explanation:

The octet rule describes the tendency of atoms of elements to react in order to have eight electrons in their valence shell. This is because having eight valence electrons confers stability to the atoms of these elements in the compounds they form.

The octet rule only does not apply to the transition elements or the inner transition elements as only the s and p electrons are involved. the electronic configuration in atoms having an octet is s²p⁶.

For example, sodium atom has one valence electron in its valence shell but a complete octet in the inner shell; it will react with chlorine atom which has seven valence electrons to form a stable compound, sodium chloride by donating its one valence electron in order to have an octet. Similarly, the chlorine atom will then have an octet by accepting the one electron from sodium atom.

7 0
3 years ago
Exactly how much time must elapse before 16 grams of potassium-42decays, leaving 2 grams of the original isotope?(1) 8 × 12.4 ho
AleksandrR [38]
The answer is <span>(3) 3 × 12.4 hours
</span>
To calculate this, we will use two equations:
(1/2) ^{n} =x
t_{1/2} = \frac{t}{n}
where:
<span>n - number of half-lives
</span>x - remained amount of the sample, in decimals
<span>t_{1/2} - half-life length
</span>t - total time elapsed.

First, we have to calculate x and n. x is <span>remained amount of the sample, so if at the beginning were 16 grams of potassium-42, and now it remained 2 grams, then x is:
2 grams : x % = 16 grams : 100 %
x = 2 grams </span>× 100 percent ÷ 16 grams
x = 12.5% = 0.125

Thus:
<span>(1/2) ^{n} =x
</span>(0.5) ^{n} =0.125
n*log(0.5)=log(0.125)
n= \frac{log(0.5)}{log(0.125)}
n=3

It is known that the half-life of potassium-42 is 12.36 ≈ 12.4 hours.
Thus:
<span>t_{1/2} = 12.4
</span><span>t_{1/2} *n = t
</span>t= 12.4*3

Therefore, it must elapse 3 × 12.4 hours <span>before 16 grams of potassium-42 decays, leaving 2 grams of the original isotope</span>
7 0
3 years ago
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Dmitry [639]
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hjlf

Answer:

0.175mol

Explanation:

Mole of a substance can be calculated using the formula as follows:

number of moles (n) = mass (m) ÷ molar mass (MM)

According to this question, there are 4.2g of Magnesium (Mg).

Molar mass of Magnesium = 24g/mol, hence, the number of moles of 4.2g of Mg is as follows:

n = 4.2g ÷ 24g/mol

n = 0.175mol

8 0
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