Answer:
4.60 J/°C g
Explanation:
This a simple calorimetry excersise. If all the heat, which is lost by the metal, is gained by the water, we assume that
Q from water = Q from metal
Q = m . C . ΔT
where C is heat capacity and ΔT, the differences between the temperatures. Let's determine the heat gained by water.
Q = 151.6 g . 4.18 J /°C g . (18.9°C - 15.6°C)
Q (+) = 2091 Joules
As this heat, was gained by the water, this heat was lost by the metal (-)
- 2091 Joules = 151.6 g . C . (Final T° - 75.3°C)
We do not know at what T° was the meta, by the end, but all the heat was gained from the water, as water was increased by 3°C, metal decreases -3°C
- 2091 Joules = 151.6 g . C . - 3°C
-2091 J / -3°C . 151.6g = 4.60 J/°C g
Answer:
The water cycle consists of 3 major processes.
**Evaporation
**Condensation.
**Precipitation.
01)Evaporation, : Evaporation is the process of a liquid s surface changing into a gas.
02)Condensation: Condensation is the process of gas changing to a liquid.
03)Precipitation: In the water cycle, water vapour in the atmosphere condenses and become liquid.
WHAT IS WATER CYCLE DO?
## The water cycle shows the continues movement of water within the Earth and atmosphere.
** Liquid Water--------------- Water vapour. ( Evaporate)
*** Condenses-------- To Clouds
( Turn)
, and precipitations back to the form of rain and snow. Water do transform around the atmosphere.
Tip::: who made the water cycle???
The sun heat.
Sadanavam1979 Greetings
Reactant concentration, the physical state of the reactants, and surface area, temperature, and the presence of a catalyst are the four main factors that affect reaction rate.
<span>9.40x10^19 molecules.
The balanced equation for ammonia is:
N2 + 3H2 ==> 2NH3
So for every 3 moles of hydrogen gas, 2 moles of ammonia is produced. So let's calculate the molar mass of hydrogen and ammonia, starting with the respective atomic weights:
Atomic weight nitrogen = 14.0067
Atomic weight hydrogen = 1.00794
Molar mass H2 = 2 * 1.00794 = 2.01588 g/mol
Molar mass NH3 = 14.0067 + 3 * 1.00794 = 17.03052 g/mol
Moles H2 = 4.72 x 10^-4 g / 2.01588 g/mol = 2.34140921086573x10^-4 mol
Moles NH3 = 2.34140921086573x10^-4 mol * (2/3) = 1.56094x10^-4 mol
Now to convert from moles to molecules, just multiply by Avogadro's number:
1.56094x10^-4 * 6.0221409x10^23 = 9.400197448261x10^19
Rounding to 3 significant figures gives 9.40x10^19 molecules.</span>
