Answer:
i going to be aniston i would say take a gess
Answer:
![P_H =2.86](https://tex.z-dn.net/?f=P_H%20%3D2.86)
![c=1.4\times 10^{-4}](https://tex.z-dn.net/?f=c%3D1.4%5Ctimes%2010%5E%7B-4%7D)
Explanation:
first write the equilibrium equaion ,
⇄ ![C_3H_5O_3^{-} +H^{+}](https://tex.z-dn.net/?f=C_3H_5O_3%5E%7B-%7D%20%20%2BH%5E%7B%2B%7D)
assuming degree of dissociation
=1/10;
and initial concentraion of
=c;
At equlibrium ;
concentration of
![[C_3H_5O_3^{-} ]= c\alpha](https://tex.z-dn.net/?f=%5BC_3H_5O_3%5E%7B-%7D%20%20%5D%3D%20c%5Calpha)
![[H^{+}] = c\alpha](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%20c%5Calpha)
![K_a = \frac{c\alpha \times c\alpha}{c-c\alpha}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cfrac%7Bc%5Calpha%20%5Ctimes%20c%5Calpha%7D%7Bc-c%5Calpha%7D)
is very small so
can be neglected
and equation is;
![K_a = {c\alpha \times \alpha}](https://tex.z-dn.net/?f=K_a%20%3D%20%7Bc%5Calpha%20%5Ctimes%20%5Calpha%7D)
= ![\frac{K_a}{\alpha}](https://tex.z-dn.net/?f=%5Cfrac%7BK_a%7D%7B%5Calpha%7D)
![P_H =- log[H^{+} ]](https://tex.z-dn.net/?f=P_H%20%3D-%20log%5BH%5E%7B%2B%7D%20%5D)
![P_H =-logK_a + log\alpha](https://tex.z-dn.net/?f=P_H%20%3D-logK_a%20%2B%20log%5Calpha)
![K_a =1.38\times10^{-4}](https://tex.z-dn.net/?f=K_a%20%3D1.38%5Ctimes10%5E%7B-4%7D)
![\alpha = \frac{1}{10}](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B1%7D%7B10%7D)
![P_H= 3.86-1](https://tex.z-dn.net/?f=P_H%3D%203.86-1)
![P_H =2.86](https://tex.z-dn.net/?f=P_H%20%3D2.86)
composiion ;
![c=\frac{1}{\alpha} \times [H^{+}]](https://tex.z-dn.net/?f=c%3D%5Cfrac%7B1%7D%7B%5Calpha%7D%20%5Ctimes%20%5BH%5E%7B%2B%7D%5D)
![[H^{+}] =antilog(-P_H)](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3Dantilog%28-P_H%29)
![[H^{+} ] =0.0014](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%20%5D%20%3D0.0014)
![c=0.0014\times \frac{1}{10}](https://tex.z-dn.net/?f=c%3D0.0014%5Ctimes%20%5Cfrac%7B1%7D%7B10%7D)
![c=1.4\times 10^{-4}](https://tex.z-dn.net/?f=c%3D1.4%5Ctimes%2010%5E%7B-4%7D)
The mass of CO₂ gas = 4.312 g
<h3>Further explanation</h3>
Reaction
NaHCO₃ (s) + HCl (aq) → NaCl (aq) + H₂O (aq) + CO₂ (g)
Find limiting reactant
mol NaHCO₃
![\tt \dfrac{8.24}{84,007 }=0.098](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B8.24%7D%7B84%2C007%20%7D%3D0.098)
mol HCl
![\tt \dfrac{4.41}{36.5}=0.121](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B4.41%7D%7B36.5%7D%3D0.121)
Limiting reactant : NaHCO₃ (smaller)
mol CO₂ = mol NaHCO₃ = 0.098
mass CO₂ :
![\tt 0.098\times 44=4.312~g](https://tex.z-dn.net/?f=%5Ctt%200.098%5Ctimes%2044%3D4.312~g)
Physical Properties<span>: </span>Physical properties<span> can be observed or measured without changing the composition of matter. </span>Physical properties<span> are used to observe and describe matter. so physical changes are the change in temperature of the land and the evaporation of water and change humidity of the air. chemical change is the ripening of the orange</span>