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3 years ago

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A block of metal has dimensions of 2 cm by 5 cm by 6 cm. The block weighs 780 g. From this information, calculate the mass, volu

me and density.

1 answer:

adoni [48]3 years ago

4 0

Answer:

mass = 78 grams

volume= 2*5*6=60cm^3

density =m/v

=78/60

13/10=1.3 g/cm^3

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How many grams of BaCl2 are required to make 1.50L of a 0.60M solution?

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187.407g

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4 0

2 years ago

Read 2 more answers

A hot 123.3 g lump of an unknown substance initially at 164.2 °C is placed in 35.0 mL of water initially at 25.0 °C and the syst

Anuta_ua [19.1K]

Answer:

The unknown substance is rhodium.

Explanation:

Heat lost by hot substance will be equal to heat gained by the water

$-Q_1=Q_2$

Mass of substance= $m_1=123.3 g$

Specific heat capacity of substance= $c_1=?$

Initial temperature of the substance = $T_1=164.2^oC$

Final temperature of substance= $T_2=T=48.6^oC$

$Q_1=m_1c_1\times (T-T_1)$

Mass of water = M

Volume of water ,V= 35 ml

Density of water = d = 1.00 g/mL

$M=d\times V=1.00 g/ml\times 35 mL=35 g$

Mass of water= $M = m_2=35 g$

Specific heat capacity of water= $c_2=4.184 J/g^oC$

Initial temperature of the water = $T_3=25.0^oC$

Final temperature of water = $T_3=T=48.6^oC$

$Q_2=m_2c_2\times (T-T_3)$

$-Q_1=Q_2$

$-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)$

On substituting all values:

we get, $c_1 =0.242 J/g^oC$

The value of heat capacity of the substance is equal to that of rhodium metal.Hence, the unknown substance is rhodium.

4 0

3 years ago