The correct order given below shows the changes that occurs in a mice population in response to changes in their environment:
- The population of mice is in an environment with many black rocks
- Mice with black for are more likely to survive and reproduce than mice with brown fur
- After many generations, most of the mice in the population have black fur
- A sandstorm covers most of the population's environment with brown sand
- Mice with black fur are less likely to survive and reproduce than mice with brown fur
- After many generations, most of the mice in the population have brown fur
<h3>What is the correct order for natural selection in the desert environment given?</h3>
Based on the process of natural selection due to envrionmental pressures, the population of the mice in the desert changes as follows before and after the environmental change:
- The population of mice is in an environment with many black rocks
- Mice with black for are more likely to survive and reproduce than mice with brown fur
- After many generations, most of the mice in the population have black fur
- A sandstorm covers most of the population's environment with brown sand
- Mice with black fur are less likely to survive and reproduce than mice with brown fur
- After many generations, most of the mice in the population have brown fur
Therefore, the correct order shows the changes that occurs in a mice population in response to changes in their environment.
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the unnamed spacecraft which travels to Mars, will have the greatest weight on the Earth.
Answer:
<u><em>Arrhenius Acid:</em></u>
According to Arrhenius concept, Acids are proton donors.
Since H₂SO₄ have a proton (H⁺ ion) and it can donate it to be made a sulphate ion, So it is an Arrhenius acid.
See the following reaction =>
<u><em>H₂SO₄ + H₂O => HSO₄ + H₃O⁺</em></u>
<u><em>Arrhenius Base:</em></u>
An Arrhenius base is a a proton acceptor.
KOH accepts the proton to to made to KOH₂ and a proton acceptor.
See the following reaction =>
<u><em>KOH + H₂o => KOH₂ + OH⁻</em></u>
<u><em></em></u>
Answer:
0.001 M OH-
Explanation:
[OH-] = 10^-pOH, so
pOH + pH = 14 and 14 - pH = pOH
14 - 11 = 3
[OH⁻] = 10⁻³ ; [OH-] = 0.001 M OH-
Answer:
Rate = 116m⁻¹s⁻¹[lactose][H]⁺
Explanation:
the formula for rate of reaction is given as
Rate = k[lactose]∧α[H]⁺∧β
we solve for the value of α and β
([lactose]₁/[lactose]₂)∧α
α = 
when we divide this equation
α = 
α = 1
we find β
R₁/R₂ = 0.01/0.02(0.001/0.001)∧β
0.00116/0.00232 = 0.5(1)∧β
β = 1
Rate = k[lactose]∧α[H]⁺∧β
we have to find the value for k
k = 0.00116/0.01(0.001)
k = 0.00116/0.00001
= 116m⁻¹s⁻¹
<u>Rate = 116m⁻¹s⁻¹[lactose][H]⁺</u>