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yKpoI14uk [10]
4 years ago
9

When 2-bromo-2-methylbutane is treated with a base, a mixture of 2-methyl-2-butene and 2-methyl-1-butene is produced. When potas

sium hydroxide is the base, 2-methyl-1-butene accounts for 45% of the product mixture. However, when potassium tert-butoxide is the base, 2-methyl-1-butene accounts for 70% of the product mixture. What percent of 2-methyl-1-butene would be in the mixture if potassium propoxide were the base
Chemistry
1 answer:
rjkz [21]4 years ago
8 0

Answer:

The percentage mixture of 2-methyl-1-butene would be in between the 45% and 70%.

Explanation:

Potassium prop oxide is the intermediate base as compared to the potassium hydroxide which is less bulky strong base and potassium tert-butoxide which is bulky base. Bulky base can minimize the substitution reaction by causing hinders the approach of carbon attack and KOH is the strong base which less effective in minimizing the substitution reaction.

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be able to meet long term timber needs.

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How you could use the scientific method to learn whether water really does take longer to boil if you are watching it.
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Salt is dissolved in a flask of tap water. Distilling the mixture causes the salt to separate from the water. Which type of ener
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3 years ago
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Describe the ammonium ion, NH4+, and the sulfate ion, SO42-. What compounds would these ions form with potassium and fluoride io
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Explanation:

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3 years ago
What are the molality and mole fraction of solute in a 22.3 percent by mass aqueous solution of formic acid (HCOOH)?
Vanyuwa [196]

Answer:

Mole fraction for solute = 0.1, or 10%

Molality = 6.24 mol/kg

Explanation:

22.3% by mass → In 100 g of solution, we have  22.3 g of HCOOH

Mass of solution = 100 g

Mass of solute = 22.3 g

Mass of solvent = 100 g - 22.3g = 77.7 g

Let's convert the mass to moles

22.3 g . 1mol/ 46 g = 0.485 moles

77.7 g. 1mol / 18 g = 4.32 moles

Total moles = 4.32 moles + 0.485 moles = 4.805 moles

Xm for solute = 0.485 / 4.805 = 0.100 → 10%

Molality → mol/ kg → we convert the mass of solvent to kg

77.7 g.  1 kg / 1000g = 0.0777 kg

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3 years ago
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