Answer: Angles who share the same initial side and terminal sides.
Answer:
b.
m<1 = 80 degrees because of the alternate angles rule.
m<2 = 100 degrees because angles on a straight line equals 180 degrees.
c.
m<1=75 degrees because again of the alternate angle rule.
m<2= 60 because that angle is equal to diagonally upper angle (I'll call it Z) and that angle would equal 60 because 180-120=60
Step-by-step explanation:
You really didn't need to do such complex math. If you want me to explain it more in detail, please let me know.
<h3><u>Question:</u></h3>
Winton was given $14 to spend at a school fair he spent 3/7 playing games how much money is left
<h3><u>Answer:</u></h3>
Amount left with winton is $ 8
<h3><u>Solution:</u></h3>
Given that Winton was given $14 to spend at a school fair
He spent 
playing games
To find: money left with Winton
From given information,
Money given to Winton = $ 14
Amount spent on games =
Thus we can say,
Amount spend on games = of total money he has
Thus he spend $ 6 on playing games
<em><u>Money left with Winton:</u></em>
Money left = total money he had - money spent on playing games
Money left = 14 - 6 = 8
Thus amount left with winton is $ 8
Answer:
True.
Step-by-step explanation:
We can represent an odd number by 2n + 1 where n = 0, 1, 2, 3, 5 etc.
Substituting:
a^2 + a = (2n + 1)^2 + 2n + 1
= 4n^2 + 4n + 1 + 2n + 1
= 4n^2 + 6n + 2
= 2(2n^2 + 3n + 1)
which is even because any integer multiplied by an even number is even.
This is also true if we use a negative odd integer:
We have 4n^2 + 4n + 1 - 1 - 2n
= 4n^2 + 2n
= 2(2n^2 + n(.
Solution:
1. Move all terms to one side
<span>25{x}^{2}+40x+16-28=0</span>
2. Simplify <span>25{x}^{2}+40x+16-28 to <span>25<span>x<span><span>2</span><span></span></span></span>+40x</span></span><span><span>−12</span></span>
<span>25{x}^{2}+40x-12=0</span>
3. Apply the Quadratic Formula<span>x=\frac{-40+20\sqrt{7}}{50},\frac{-40-20\sqrt{7}}{50}
</span>
4. Simplify solutions
<span>x=-\frac{2(2-\sqrt{7})}{5},-\frac{2(2+\sqrt{7})}{5}</span>
Done!
