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Ivahew [28]
3 years ago
6

Calculate the acceleration of Josh riding his bicycle in a straight line that speeds up from 4 m/s to 6 m/s in 5 seconds. Initia

l Speed ____. Final Speed ______. Time ______. Acceleration =________
Chemistry
1 answer:
drek231 [11]3 years ago
8 0

Answer:

Initial Speed ____4m/s. Final Speed ______6m/s. Time ______5 seconds . Acceleration =________0.4m/s²

Explanation:

The acceleration is the rate of change of velocity during time t .

acceleration = Final velocity- Initial velocity/ Time

                    = Vf- Vi/ t

            a = Δv/ Δt

                   = 6m/s- 4m/s/ 5s

                   = 2m/s/ 5s

                  = 0.4m/s²

It can also be defined as the difference of the initial and final velocity ( velocities measured in meters per second) during the given time t measured in seconds .The SI unit of acceleration is meter per second squared.

If the velocities are not measured in meters per second or time is not measured in seconds then the units are changed accordingly.

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Will give brainliest to correct answer of this picture:
Katyanochek1 [597]

Answer:

option C : cellular respiration

Explanation:

cellular respiration is taking place in this diagram .

as in respiration food get oxidised to release energy and it releases CO2 and water

7 0
3 years ago
How much of glucose (C6H1206) is needed to make 1 L of a 1-M solution? Use details to support your answer.
Yakvenalex [24]

Answer:

200 g C₆H₁₂O₆

General Formulas and Concepts:

<u>Chemistry - Solutions</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Molarity = moles of solute / liters of solution

Explanation:

<u>Step 1: Define</u>

1 M C₆H₁₂O₆

1 L of solution

<u>Step 2: Identify Conversions</u>

Molar Mass of C - 12.01 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar mass of C₆H₁₂O₆ - 6(12.01) + 12(1.01) + 6(16.00) = 180.18 g/mol

<u>Step 3: Find moles of solute</u>

1 M C₆H₁₂O₆ = x mol C₆H₁₂O₆ / 1 L

x = 1 mol C₆H₁₂O₆

<u>Step 4: Convert</u>

<u />1 \ mol \ C_6H_{12}O_6(\frac{180.18 \ g \ C_6H_{12}O_6}{1 \ mol \ C_6H_{12}O_6} ) = 180.18 g C₆H₁₂O₆

<u>Step 5: Check</u>

<em>We are given 1 sig figs. Follow sig fig rules and round.</em>

180.18 g C₆H₁₂O₆ ≈ 200 g C₆H₁₂O₆

3 0
3 years ago
(tco 1) isotopes of an element have the same number of _____ and different numbers of _____.
seropon [69]
Protons and neutrons.  Hope this helps!!!
7 0
3 years ago
Use Boyle's Law to explain what would happen to the volume of a helium- filled balloon if it was carried underwater by a diver t
oksano4ka [1.4K]

The deeper the diver takes the helium balloon, the more it reduces in size. This is due to the pressure of the water column above pressing on the balloon. According to Boyle’s law (P= k*1/V.), as the volume of the balloon decreases, the pressure of the helium inside increases.

4 0
3 years ago
Seawater has a ph of 8.1. what is the concentration of oh–?
lara31 [8.8K]
PH scale is used to determine how acidic or basic a solution is.
pH can be calculated as follows;
by knowing the ph we can calculate pOH
pH + pOH = 14
pOH = 14 - 8.1 
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pOH is used to calculate the hydroxide ion concentration 
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[OH⁻] = antilog(-pOH)
[OH⁻] = 1.26 x 10⁻⁶ M
therefore hydroxide ion concentration is 1.26 x 10⁻⁶ M
4 0
3 years ago
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