1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rudiy27
3 years ago
6

What is the source of all electromagnetic waves?

Physics
1 answer:
kherson [118]3 years ago
6 0

Answer:

Accelerating charges.

Explanation:

Electromagnetic waves are waves produced by the vibration of both electrical and magnetic fields.

This interaction produces an energy source that does not require any medium to propagate.

To produce electromagnetic waves, electric and magnetic fields must be vibrating.

An electric charge produced when vibrating under voltage will produce electromagnetic waves. This is the same for all sources of these waves.

The sun produces electromagnetic waves. A lot of human activities also does this.

You might be interested in
How reactive is an atom of Sodium(Na) and why?
lara [203]
Sodium (Na) is very reactive because it does not have a full valence shell.
6 0
3 years ago
An unknown substance has a mass of 11.9 g . When the substance absorbs 1.071×102 J of heat, the temperature of the substance is
Mashcka [7]

Answer: The most likely identity of the substance is iron.

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed=1.071\times 10^2 Joules

m= mass of substance = 11.9 g

c = specific heat capacity = ?

Initial temperature of the water = T_i = 25.0°C

Final temperature of the water = T_f  = 45.0°CChange in temperature ,\Delta T=T_f-T_i=(45-25)^0C=20^0C

Putting in the values, we get:

1.071\times 10^2=11.9\times c\times 20^0C

c=0.45J/g^0C

The specific heat of 0.45 is for iron and thus the substance is iron.

3 0
3 years ago
according to newton's third law, when a horse pulls on a cart, the cart pulls back on the horse with an equal force on the horse
Debora [2.8K]
Based on Newton's principle, whenever objects A and B interact with each other, they exert forces upon each other.

When a horse pulls on a cart, t<span>he horse exerts a force only to the cart. But that force applies only to the cart, not to the horse.
 
The cart in turn exerts a force on the horse. But that force applies only to the horse, not the cart also.
</span>
There are two forces resulting from this interaction - a force on the horse and a force on the cart. T<span>he net force on the cart remains as it was --- a positive force in the direction of the horse's movement. Therefore, the cart begins to accelerate and move.</span><span>


</span>
8 0
3 years ago
Which of the following measurements changes based on the strength of gravity? A.Mass B.Size C.Length D.Weight
kaheart [24]
Weight. As a scientific term Weight is referred to as the force that Earth and objects have with each other. Your weight can be different on other planets.
7 0
3 years ago
Read 2 more answers
Cesium-137 undergoes beta decay and has a half-life of 30.0 years. How many beta particles are emitted by a 14.0-g sample of ces
Mandarinka [93]

Answer: 0.81\times 10^{16} beta particles

Explanation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass = 14.0 g

Molar mass = 137 g/mol

\text{Number of moles of cesium}=\frac{14.0g}{137g/mol}=0.102moles

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

1 mole of cesium contains atoms =  6.023\times 10^{23}

0.102 moles of cesium contains atoms =  \frac{6.023\times 10^{23}}{1}\times 0.102=0.614\times 10^{23}

The relation of atoms with time for radioactivbe decay is:

N_t=N_0\times \frac{1}{2}^{\frac{t}{t_{\frac{1}{2}}}}

Where N_t =atoms left undecayed

N_0 = initial atoms

t = time taken for decay = 3 minutes

{t_{\frac{1}{2}}} = half life = 30.0 years = 1.577\times 10^7 minutes

The fraction that decays  :  1-(\frac{1}{2})^{\frac{3}{1.577\times 10^7}}=1.32\times 10^{-7}

Amount of particles that decay is  = 0.614\times 10^{23}\times 1.32\times 10^{-7}=0.81\times 10^{16}

Thus 0.81\times 10^{16} beta particles are emitted by a 14.0-g sample of cesium-137 in three minutes.

7 0
2 years ago
Other questions:
  • How do scientists classify small objects in the solar system?
    12·1 answer
  • A woman is standing on a steep hillside in the rain and is not moving. A
    8·1 answer
  • A particle starts from the origin at t = 0 with an initial velocity of 5.3 m/s along the positive x axis.If the acceleration is
    11·1 answer
  • Ball B is suspended from a cord of length l attached to cart A, which can roll freely on a frictionless, horizontal track. The b
    15·1 answer
  • A burning candle is covered by a jar as shown in the picture. The whole arrangement has a mass of 500 g. What will be the approx
    15·2 answers
  • If neutron stars are squeezed harder they collapse into black hole; how would this transition occur?
    15·1 answer
  • Define electric field intensity​
    8·1 answer
  • (b) Which statement about beta radiation is true?
    15·1 answer
  • According to the chart which type of electromagnetic wave has a longest wavelength?
    6·1 answer
  • A circuit in a radio receiver requires a current of at least 1.0 microamp in order to detect a signal. How many electrons pass t
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!