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Rudiy27
3 years ago
6

What is the source of all electromagnetic waves?

Physics
1 answer:
kherson [118]3 years ago
6 0

Answer:

Accelerating charges.

Explanation:

Electromagnetic waves are waves produced by the vibration of both electrical and magnetic fields.

This interaction produces an energy source that does not require any medium to propagate.

To produce electromagnetic waves, electric and magnetic fields must be vibrating.

An electric charge produced when vibrating under voltage will produce electromagnetic waves. This is the same for all sources of these waves.

The sun produces electromagnetic waves. A lot of human activities also does this.

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PLEASE HELP ME I AM TIMED!
Leno4ka [110]

Answer:

Well my good friend the other person did not give U a good answer, it is actually the third one

Explanation: well it is the most logical of all the answers if you think about it and a lot of the creatures we have in the water today are thought of to have once lived on land based on the fossils we still find to this very day my friend

3 0
3 years ago
To practice Problem-Solving Strategy 21.1 Coulomb's Law. Three charged particles are placed at each of three corners of an equil
Salsk061 [2.6K]

Answer:

The force felt by charge 3 is F=(-5.6*10⁻⁶,3.36⁻⁵)N

Explanation:

As the superposition principle applies to static charges, we can find the net electric force as the sum of the two forces felt by q3.

Looking at the drawing and knowing that they form an equilateral triangle of lenght 4 we can conclude that each internal angle is 60°.

So, the positions in our coordinate system are:

r_1=(0,0)\\r_2=(4\ cos(60\°),4\ sin(60\°))\\r_3=(4,0)\\

Now  using Coulomb's force:

F_{ij}=\frac{-kq_iq_j}{d^2}(\vv{r}_j-\vv{r}_i)

Where d=4, q1 = -7.8*10⁻⁹C, q2 = -15.6 *10⁻⁹C, q3 = 8.0 *10⁻⁹C, k=8.98*10⁹, e0=8.8*10¹⁰:

Replacing we get 2 equations:

F_{13}=\frac{-kq_1q_3}{d^2}(\vv{r}_1-\vv{r}_3)=\frac{-kq_1q_2}{d^2}(-0.04\ cos(60\°),-0.04\ sin(60\°))\\\\F_{23}=\frac{-kq_2q_3}{d^2}(\vv{r}_1-\vv{r}_3)=\frac{-kq_1q_2}{d^2}(0.04-0.04\ cos(60\°),-0.04\ sin(60\°))\\

To work with the sam

F=∑F_i=3.5*10⁻⁴(0.023,0.032)+7*10⁻⁴(-0.016,0.032)=

=((3.5*10⁻⁴-7*10⁻⁴)*0.016,(3.5*10⁻⁴+7*10⁻⁴)*0.032)=

F=(-5.6*10⁻⁶,3.36⁻⁵)N

7 0
3 years ago
An object is in uniform circular motion, tracing an angel at 30 degrees every 0.010 seconds. What's the period of this motion an
Neko [114]
Here's the rule you need to know
in order to answer this question:

                     1 full circle ==> 360 degrees .

Got that ?

Now you could set up a proportion:

     (30 degrees) / (0.01 second)  =  (360 degrees) / (time for full period)

Cross-multiply the proportion:

     (30°) · (period)  =  (360°) · (0.01 sec)

Divide each side by (30°) :    Period = (360° · 0.01 sec) / (30°)

                                                     =  (3.6° · sec) / (30°)

                                                     =  (3.6 / 30)  sec

                                                     =      0.12  sec .
___________________________________

Another way to look at it:

30°        takes    0.01 second
60°        takes    0.02 second
90°        takes    0.03 second
120°      takes    0.04 second
150°      takes    0.05 second
180°      takes    0.06 second
210°      takes    0.07 second
240°      takes    0.08 second
270°      takes    0.09 second
300°      takes    0.10 second
330°      takes    0.11 second
360°      takes   0.12 second

7 0
4 years ago
As you climb a mountain, you can expect the air temperature to decrease by 6.5 degrees C for every 1000 meters you ascend. This
Reptile [31]

Answer:

the answer will be C.  4 degrees C

Explanation:

you subtract base meters from peak meters to get 4 meters; then Multiply 6.5 by 4.

Then subtract that total from 30 degrees C

***as altitude increases, temperature decreases***

6 0
3 years ago
16. A 95kg fullback, running at 8.2m/s, collided in midair with a 128 kg defensive tackle moving in the opposite direction. Both
Daniel [21]

a) 779 kg m/s

The momentum of an object is given by:

p = mv

where

m is the mass of the object

v is its velocity

For the fullback before the collision,

m = 95 kg

v = 8.2 m/s

Therefore, his momentum was:

p=mv=(95)(8.2)=779 kg m/s

b) -779 kg m/s

After the collision, both the fullback and the tackle come to a stop: this means that their momentum after the collision is zero,

p' = 0

The initial momentum of the fullback was

p = 779 kg m/s

Therefore, his change in momentum is

\Delta p = p' -p =0-779  = -779 kg m/s

where the negative sign indicates that the direction is opposite to the initial direction of motion.

c) -779 kg m/s

Here we can apply the law of conservation of momentum. In fact, the total momentum before and after the collision must be conserved. So we can write:

p_f + p_t = p'

where

p_f is the initial momentum of the fullback

p_t is the initial momentum of the tackle

p' is the final combined momentum after the collision

We already know that

p_f = 779 kg m/s\\p' = 0

Therefore, we can find the tackle's original momentum:

p_t = p'-p_f = 0-(779) = -779 kg m/s

where the negative sign indicates that the direction is opposite to the initial direction of motion of the fullback.

e) -6.1 m/s

To find the velocity of the tackle, we can use again the equation of the momentum:

p = mv

where here we have

p=-779 kg m/s is the original momentum of the tackle

m = 128 kg is his mass

Solving the equation for v, we find the tackle's original velocity:

v=\frac{p}{m}=\frac{-779}{128}=-6.1 m/s

So, he was moving at 6.1 m/s in the direction opposite to the fullback.

4 0
3 years ago
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