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enot [183]
1 year ago
5

The density of a material is a/an ___________.

Chemistry
1 answer:
Nitella [24]1 year ago
5 0

The density of a material is an intensive property.

<h3>What is intensive property?</h3>

An intensive property of matter is one that does not change with the amount of matter. It is a bulk property, which means that it is a physical property that is independent of sample size or mass. An extensive property, on the other hand, is one that is affected by sample size.

<h3>What factors influence an intensive property?</h3>

Intensive properties are those that are determined solely by the characteristics of the material and not by its quantity - for example, density, temperature, refractive index, color, and pressure. Intensive properties are not additive, which means their value does not change when the amount of material is changed.

Learn more about the intensive property here:-

brainly.com/question/24909279

#SPJ4

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I have a very question what is the viruz more dangerous for the word
MrMuchimi

Lassa fever is extremely dangerous (please note researchers have a rough time correctly determing how dangerous a virus is because many have not had a major outbreak and a vrius will react differently to everyones body.)

7 0
3 years ago
Alkaline earth metals electronegativity
Alex

It is usually measured on the Pauling scale, on which the most electronegative element (fluorine) is assigned an electronegativity of 4.0. Each of these elements has a low electronegativity on the Pauling scale, and the electronegativities clearly decrease down the group.

7 0
4 years ago
One mole of an ideal gas, for which CV,m = 3/2R, initially at 298 K and 1.00 × 105 Pa undergoes a reversible adiabatic compressi
oksian1 [2.3K]

Answer:

  • final temperature (T2) = 748.66 K
  • ΔU = w = 5620.26 J
  • ΔH = 9367.047 J
  • q = 0

Explanation:

ideal gas:

  • PV = RTn

reversible adiabatic compression:

  • δU = δq + δw = CvδT

∴ q = 0

∴ w = - PδV

⇒ δU = δw

⇒ CvδT = - PδV

ideal gas:

⇒ PδV + VδP = RδT

⇒ PδV = RδT - VδP = - CvδT

⇒ RδT - RTn/PδP = - CvδT

⇒ (R + Cv,m)∫δT/T = R∫δP/P

⇒ [(R + Cv,m)/R] Ln (T2/T1) = Ln (P2/P1) = Ln (1 E6/1 E5) = 2.303

∴ (R + Cv,m)/R = (R + (3/2)R)/R = 5/2R/R = 2.5

⇒ Ln(T2/T1) = 2.303 / 2.5 = 0.9212

⇒ T2/T1 = 2.512

∴ T1 = 298 K

⇒ T2 = (298 K)×(2.512)

⇒ T2 = 748.66 K

⇒ ΔU = Cv,mΔT

⇒ ΔU = (3/2)R(748.66 - 298)

∴ R = 8.314 J/K.mol

⇒ ΔU = 5620.26 J

⇒ w = 5620.26 J

  • H = U + nRT

⇒ ΔH = ΔU + nRΔT

⇒ ΔH = 5620.26 J + (1 mol)(8.314 J/K.mol)(450.66 K)

⇒ ΔH = 5620.26 J + 3746.787 J

⇒ ΔH = 9367.047 J

8 0
3 years ago
- Ibrahim and Emmanuel have been investigating the amount of copper sulfate that
nignag [31]

The boys can arrive at the conclusion that as temperature increases, a greater mass of copper sulfate is dissolved in water.

<h3>What is an experiment?</h3>

An experiment is a scientific investigation that seeks to obtain cause and effect relationships. There must be a dependent and an independent variable in every experiment.

The average of the temperature readings is; 20 + 30 + 40 + 50 + 60 + 70 + 80/7 =  50

They used an interval of 10 degrees for the temperature readings. The boys should have kept the heating time the same. The independent variable in this experiment is the temperature. The boys can arrive at the conclusion that as temperature increases, a greater mass of copper sulfate is dissolved in water.

Learn more about dependent and independent variables: brainly.com/question/967776

8 0
2 years ago
How many significant digits in 0.23100
Reil [10]

Answer:

There are 5 significant digits in 0.23100.

Explanation:

This is because all non-zero digits are considered significant and zeros after decimal points are considered significant.

4 0
3 years ago
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