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3 years ago

CLICK ON THISS!!!!!!!!

Mathematics

1 answer:

Assoli18 [71]3 years ago

6 0

Answer:

I did itttttt:0

Step-by-step explanation:

Thanks for free points

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ANEK [815]

Answer:

$\frac{2}{ |1 - x| \times |1 - x| } =$

$= \frac{2}{ |1 - x|^{2} }$

$\frac{2}{ |1 - x| \times |1 - x| } =$

$= |1 - x| \times |1 - x| = 0$

$= |1 - x |^{2} = 0$

$= |1 - x| = 0$

$= 1 - x = 0$

$= ( - x) = ( - 1)$

$x = 1$

Step-by-step explanation:

I Hope This Help

7 0

3 years ago

The perimeter of a rectangle is 40cm. If the length were doubled and the width halved, the perimeter would be increased by 16cm.

Arada [10]

Answer:

The dimensions of the original rectangle are Length =12cm, Width=8cm

Step-by-step explanation

Let the length of the rectangle be x

Let the width of the rectangle be y

The perimeter of a rectangle is 40cm.

2(x+y)=40

Divide both sides by 2

x+y=20

If the length were doubled(2x) and the width halved(y/2), the perimeter would be increased by 16cm,i.e.(40+16)cm

Therefore:

Divide both sides by 2

From the first equation, x=20-y.

Substitute x=20-y into

7 0

3 years ago

The given point in on the graph of y=f(x). Find a point on the graph of y=g(x)

Tema [17]

Answer: b

Step-by-step explanation:

anser is b

8 0

3 years ago

Y=2/3(x-5)^2

Anvisha [2.4K]

Answer:

see below

Step-by-step explanation:

The graph opens upward if the sign of the squared term is positive. If that sign is negative, the graph opens downward. The first three equations open upward; the last opens downward.

The line of symmetry is the value of x that makes the squared term zero. Here, that is x=5 for all equations.

y=2/3(x-5)^2: A, D

y=1/2(x-5)^2: A, D

y=3/4(x-5)^2: A, D

y=-4(x-5)^2: B, D

8 0

3 years ago

Can someone help! I know the answer I just need step by step!

baherus [9]

Answer:

$4 \sqrt{2}$

Step-by-step explanation:

Rewrite 32 as the product of 16 and 2:

$\implies \sqrt{32}=\sqrt{16 \cdot 2$

Apply exponent rule $\sqrt{a \cdot b}=\sqrt{a}\sqrt{b}$

$\implies \sqrt{16 \cdot 2}=\sqrt{16}\sqrt{2}$

Rewrite 16 as 4²:

$\implies \sqrt{16}\sqrt{2}=\sqrt{4^2}\sqrt{2}$

Apply exponent rule $\sqrt{a^2}=a$

$\implies \sqrt{4^2}\sqrt{2}=4 \sqrt{2}$

6 0

2 years ago

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