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svetoff [14.1K]
2 years ago
9

Y = 4x 4x^2 + y = 20

Mathematics
1 answer:
Romashka [77]2 years ago
4 0

Answer:

8X=4Y

Step-by-step explanation:

JUST ADD

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Are the following figures similar?
iris [78.8K]

Answer:

the answer is "D"

Step-by-step explanation:

3 0
3 years ago
If s(x) = 2 - x and t(x) = 3x, which value is equivalent to (s•f)(-7)?
erica [24]

Answer:

Step-by-step explanation:

t(-7)= 3(-7)= -21

s(-21)= 2-(-21)= 2 + 21= 23

4 0
8 months ago
Plzz help steps if possible if not its ok j=i just need to pass this class
hammer [34]

Answer:

\text{(B) }\cos 40^{\circ}=\frac{x}{60}

Step-by-step explanation:

In any triangle, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse (longest side) of the triangle. (a/h)

The angle marked 40 degrees has an adjacent side of x and the hypotenuse of the triangle is 60.

Therefore, we have the equation:

\boxed{\cos 40^{\circ}=\frac{x}{60}}

6 0
3 years ago
Find (f-g)(x) if f(x)=3x-5 and g(x)=x2-5x+4
solmaris [256]

Answer:

Step-by-step explanation:

Hello,

(f-g)(x)=f(x)-g(x)=3x-5-(x^2-5x+4)\\\\=3x-5-x^2+5x-4\\\\=-x^2+8x-9

Thanks

4 0
3 years ago
In a triangle, two sides that measure 8 centimeters and 11 centimeters form an angle that measures 82°. to the nearest tenth of
Gwar [14]
We can use the Сosine formula to solve this problem.
<span>First we must find the third side (АС) of the triangle:
</span>
AC^2=AB^2+BC^2-2*AB*BC*cos82^o \\ AC^2=8^2+11^2-2*8*11*0.1392 \\ AC^2=64+121-24.4992= 160.508 \\ AC= \sqrt{160.508} \approx  12.67 \ cm
<span>
The smallest angle of the triangle lies opposite the smallest side, so we need to find m</span>∠C.

cosC= \frac{AC^2+BC^2-AB^2}{2*AC*BC}  \\  \\ cosC= \frac{12.67^2+11^2-8^2}{2*12.67*11}= \frac{160.53+121-64}{278.74} = \frac{217.53}{278.74} \approx  0.7804

Now we can use Bradis's Table (I don't know the name in English, maybe Trigonometric Table?) to find m∠C:

m∠С = 38°42' = 38.7°

Answer: 38.7°


<span>I hope this helps</span>

7 0
3 years ago
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