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posledela
3 years ago
8

Effective management of worker safety and health programs has

Engineering
1 answer:
Tom [10]3 years ago
6 0

Answer:

Four components: Management leadership and employee involvement. Analysis of work site to identify hazards. Hazard prevention and control to protect workers from hazards.

Explanation:

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Three natural materials that were used by early man as roof covering​
olga55 [171]

Explanation:

animal parts, wood, rock, and clay

8 0
3 years ago
Read 2 more answers
A 15-ft beam weighing 570 lb is lowered by means of two cables unwinding from overhead cranes. As the beam approaches the ground
7nadin3 [17]

Answer:

I. Tension (cable A) ≈ 6939 lbf

II. Tension (cable B) ≈ 17199 lbf

Explanation:

Let's begin by listing out the data that we were given:

mass of beam (m) = 570 lb, deceleration (cable A) = -20 ft/s², deceleration (cable B) = -2 ft/s²,

g = 32.17405 ft/s²

The tension on an object is given by the product of mass of the object by gravitational force plus/minus the product of mass by acceleration.

Mathematically represented thus:

T = mg + ma

where:

T = tension, m = mass, g = gravitational force,

a = acceleration

I. For Cable A, we have:

T = mg + ma = (570 * 32.17405) + [570 * (-20)]

T = 18339.2085 - 11400 = 6939.2085

T ≈ 6939 lbf

II. For Cable B, we have:

T = mg + ma = (570 * 32.17405) + [570 * (-2)]

T = 18339.2085 - 1140 = 17199.2085

T ≈ 17199 lbf

4 0
4 years ago
"Carbon 14 (C-14), a radioactive isotope of carbon, has a half-life of 5730 ± 40 years. Measuring the amount of this isotope lef
igor_vitrenko [27]

Answer:

The age of the bones is approximately 14172 years.

Explanation:

The age of the bones can be determinated using the following decay equation:

N_{(t)} = N_{0}e^{-\lambda t}   (1)

<u>Where:</u>

N(t): is the quantity of C-14 at time t

No: is the initial quantity of C-14  

λ: is the decay rate      

t: is the time

First, we need to find λ:

\lambda = \frac{ln(2)}{t_{1/2}}

<u>Where:</u>

t(1/2): is the half-life of C-14 = 5730 y

\lambda = \frac{ln(2)}{5730 y} = 1.21 \cdot 10^{-04} y^{-1}

Now, we can calculate the age of the bones by solving equation (1) for t:

t = \frac{-ln(\frac{N_{(t)}}{N_{0}})}{\lambda}

We know that the bones have lost 82% of the C-14 they originally contained, so:

N_{t} = (1 - 0.82)N_{0} = 0.18N_{0}

t = \frac{-ln(0.18)}{1.21 \cdot 10^{-04} y^{-1}}

t = 14172 y

Therefore, the age of the bones is approximately 14172 years.

I hope it helps you!

3 0
3 years ago
Detail a high-end design project and what paper and finishing techniques you would use include your choices for matte or gloss v
DochEvi [55]

Answer   what do you want i know a project but what is it on?

Explanation:

5 0
3 years ago
2.11 Consider a 400 mm × 400 mm window in an aircraft. For a temperature difference of 90°C from the inner to the outer surface
alexandr402 [8]

Answer:

The heat loss rate through one of the windows made of polycarbonate is 252W. If the window is made of aerogel, the heat loss rate is 16.8W. If the window is made of soda-lime glass, the heat loss rate is 1190.4W.

The cost associated with the heat loss through the windows for an 8-hour flight is:

For aerogel windows: $17.472 (most efficient)

For polycarbonate windows: $262.08

For soda-lime glass windows: $1,238.016 (least efficient)

Explanation:

To calculate the heat loss rate through the window, we can use a model of heat transmission by conduction throw flat wall. Using unidimensional Fourier law:

\frac{dQ}{dt}=\dot Q =-kS\nabla \vec{T}

In this case:

\dot Q =k\frac{S}{L} \Delta T

If we replace the data provided by the problem we get the heat loss rate through one of the windows of each material (we only have to change the thermal conductivities).

To obtain the thermal conductivity of the soda-lime glass we use the graphic attached to this answer (In this case for soda-lime glass k₃₀₀=0.992w/m·K).

To calculate the cost associated with the heat loss through the windows for an 8-hour flight we use this formula (using the heat loss rate calculated in each case):

Cost=C_{hc}\cdot \dot Q \cdot t \cdot n=1\frac{\$}{Kwh} \cdot \dot Q \cdot 8h \cdot 130

6 0
3 years ago
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