Answer:
See attachment for completed question
Explanation:
Given that; Brainly.com
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mkasblog
College Engineering 5+3 pts
The dry unit weight of a soil sample is 14.8 kN/m3.
Given that G_s = 2.72 and w = 17%, determine:
(a) Void ratio
(b) Moist unit weight
(c) Degree of saturation
(d) Unit weight when the sample is fully saturated
See complete solving at attachment
Answer:
YES
Explanation:
If we connect batteries in series then the output voltage is the sum of the individual voltage of each battery i.e if you connect three 12 volts batteries in series then their output voltage will be 12+12+12=36 volts, but the current rating of the batteries in series will be same of the individual battery rating in 'mah'.
But when we connect the batteries in parallel their voltage is not added but their current rating in mah is addition of their individual rating.
So, If you want 24 volts from three 12 volts battery then you can connect two of them in series and the other one in parallel with them this will give 24 volts and the current will be addition of the two series batteries and the third which is in parallel with them. You can use this configuration if current value is not a big factor.
Answer:
The final temperature of water is 381.39 °C.
Explanation:
Given that
Mass of water = 5 kg
Heat transfer at constant pressure Q = 2960 KJ
Initial temperature = 240 °C
We know that heat transfer at constant pressure given as follows

We know that for water

Lets take final temperature of water is T
So


T=381.39 °C
So the final temperature of water is 381.39 °C.
is the volume of the sample when the water content is 10%.
<u>Explanation:</u>
Given Data:

First has a natural water content of 25% =
= 0.25
Shrinkage limit, 

We need to determine the volume of the sample when the water content is 10% (0.10). As we know,
![V \propto[1+e]](https://tex.z-dn.net/?f=V%20%5Cpropto%5B1%2Be%5D)
------> eq 1

The above equation is at
,

Applying the given values, we get

Shrinkage limit is lowest water content

Applying the given values, we get

Applying the found values in eq 1, we get


Answer:
<em><u>The 'shoulder' of a road is the land to the edge of the road. On most roads without pavements, the shoulder is a strip of grass or a hedgerow. This is known as a 'soft shoulder'. On a motorway, this strip of land is hardstanding, hence the name 'hard shoulder.'</u></em>
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