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maria [59]
3 years ago
13

Can someone tell me plz :P

Chemistry
1 answer:
NemiM [27]3 years ago
8 0

Answer:

There's nothing there

Explanation:

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If you have 2.4L of SO2 gas (at STP) how many moles of sulfur dioxide do you have?
Andru [333]

Answer:

0.107 mole of SO2.

Explanation:

1 mole of a gas occupy 22.4 L at standard temperature and pressure (STP).

With the above information, we can simply calculate the number of mole of SO2 that will occupy 2.4 L at STP.

This can be obtained as follow:

22.4 L contains 1 mole of SO2.

Therefore, 2.4 L will contain = 2.4/22.4 = 0.107 mole of SO2.

Therefore, 0.107 mole of SO2 is present in 2.4 L at STP.

4 0
3 years ago
This is science talking about rocks<br> extrusive<br> or<br> Intrusive
elena-14-01-66 [18.8K]
It’s intrusive, and is one that forms when magma cools within Earth
6 0
3 years ago
In a solution, which pair of actions could combine to keep a concentration constant?
insens350 [35]

Answer:

B: Adding water, then adding solute

Explanation:

This is because, say you have a solution with a certain concentration.

If you add more water, it will become more diluted (less concentrated)

If you add more solute, it will become more concentrated.

Therefore if you add water and solute, it could cancel out, and the concentration would remain the same.

Hope this helps! Let me know if you have any questions/ would like anything further explained :)

6 0
2 years ago
How many moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm?
marshall27 [118]

Moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm is  021.65 mole

Mole is the unit of amount of substances of specified elementary entities

According to the ideal gas law he number of moles of a gas n can be calculated knowing the partial pressure of a gas p in a container with a volume V at an absolute temperature T from the equation

n =pV/RT

Here given data is volume = 87.1 liters

Temperature = 74 °C means 347.15 k

Pressure = 3.5 atm

R = 0.0821

Putting this value in ideal gas equation then

n =pV/RT

n =  3.5 atm×87.1 liters / 0.0821 ×347.15 k

n = 021.65 mole

Moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm is  021.65 mole

Know more about mole of helium

brainly.com/question/23365554

#SPJ1

8 0
9 months ago
A 2.50 L solution contains 5.00 g of NaOH, which has a molecular weight of 40.00
Fantom [35]

Answer:

0.313mol/L

Explanation:

\frac{5.00}{40.00}  \times  2.50 = 0.3125

3 0
2 years ago
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