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3 years ago

Because of its high heat content, the most valuable type of coal is __________.

1 answer:

8 0

C.
Anthracite has the highest carbon compact and fewest impurities.
Also, the highest calorific of all types of coal except for graphite.

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Choose a likely identity for X, Y, and Z in these structures. A central X atom is bonded to two chlorine atoms through single bo

11111nata11111 [884]

Answer:

X= Be

Y= B

Z=O

Explanation:

From the description of the compound XCl2, among the options listed only beryllium can form such compound with three lone pairs in the two chlorine atoms and no lone pair on the central atom X.

From the description of YCl3, only Boron among the options listed can form such a compound with no lone pair on the central atom and three lone pairs on each of the chlorine atoms.

From the description of ZCl2, only oxygen forms the compound OCl2 among the elements listed where oxygen possesses two lone pairs and each chlorine atom possesses three lone pairs each.

8 0

3 years ago

A or B or C or D, fassst plzzz

olga nikolaevna [1]

Answer:

a.option is the correct answer

4 0

2 years ago

Read 2 more answers

Write a word equation for the chemical reaction. I’ll brainlist.

Alex

Answer:

potassium hydroxide + sulfuric acid → potassium sulfate + water.

Explanation:

Hope it helps.. if yes, plz mark me as brainliest

5 0

3 years ago

How many grams of material is lost in the aqueous phase if two extractions are carried out on 100 mL of a 5% (m/v) aqueous solut

san4es73 [151]

Answer:

4.94g of material

Explanation:

Partition coefficient (Kp) of a substance is defined as the ratio between concentration of organic solution and aqueous solution, that is:

Kp = 8 = Concentration in Ethyl acetate / Concentration in water

100mL of a 5% solution contains 5g of material in 100mL of water. Thus:

8 = X / 100mL / (5g-X) / 100mL

Where X is the amount of material in grams that comes to the organic phase.

8 = X / 100mL / (5g-X) / 100mL

8 = 100X / (500-100X)

4000 - 800X = 100X

4000 = 900X

4.44g = X

Thus, in the first extraction you will lost 4.44g of material from the aqueous phase.

And will remain 5g-4.44g = 0.56g.

In the second extraction:

8 = X / 100mL / (0.56g-X) / 100mL

8 = 100X / (56-100X)

448 - 800X = 100X

448 = 900X

0.50g = X

In the second extraction, you will extract 0.50g of material

Thus, after the two extraction you will lost:

4.44g + 0.50g = 4.94g of material

6 0

2 years ago

Morgan wants to compare the weather conditions at her school each day during the week. She decides to measure and record weather

Firlakuza [10]

Answer: Air Temperature

8 0

3 years ago